
Please help...
The Fibonacci sequence problem: The Fibonacci sequence is the series of numbers 0, 1, 1, 2, 3, 5, 8, .... Formally, it can be expressed as:
fib0 = 0
fib1 = 1
fib2 = fibn1 + fibn2
Write a C program using the fork() system call that generates the Fibonacci sequence in the child process. The number of the sequence will be provided in the command line. For example, if 5 is provided, the first five numbers in the Fibonacci sequence will be output by the child process. Because the parent and child processes have their own copies of the data, it will be necessary for the child to output the sequence. Have the parent invoke the wait() call to wait for the child process to complete before exiting the program. Perform necessary error checking to ensure that a nonnegative number is passed on the command line.

OK, so can you say solve this without using fork() ?


So you said.
But do we have to explain the basic problem of displaying the Fibonacci series first, or can we get to the point by you showing us what you've managed to far and then we can help you with the next step of making use of fork().

hi
that shouldn't be too hard
Code:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main()
{
int n;
printf("please enter the number n\n");
scanf("%d",&n);
if (n<=0)
{
printf("moron!\n");
return 1;
}
pid_t pid = fork();
if (pid == 0)
{
/*child process*/
/*here we print out the fibonacci numbers, which i would do like this*/
printf("fibonaccinumbers up to %d:\n",n);
int *fib_array = (int*)malloc(sizeof(int)*n);
int i;
for (i=0;i<n;i++)
{
if (i<=1)
fib_array[i] = 1;
else
fib_array[i] = fib_array[i1]+fib_array[i2];
printf("%d\n",fib_array[i]);
}
free(fib_array); /*not really neccessary, but anyway*/
exit(0);
}
if (pid < 0)
{
printf("error forking child\n");
return 1;
}
if (pid > 0)
{
/*parent process*/
int status;
wait(&status);
printf("now the child process has exited with the status %d\n",status);
return 0;
}
}
cheers
maklolm

It's not a question of being easy, it's a matter of the OP learning to do the homework for themselves and not being spoonfed a complete answer right off the bat.
Not that it matters, it seems the OP has already gotten lucky elsewhere as well.
