awk problem

This is a discussion on awk problem within the Linux Programming forums, part of the Platform Specific Boards category; I have the following awk script that sets a flag to 1 if Left is matched on a line, until ...

  1. #1
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    awk problem

    I have the following awk script that sets a flag to 1 if Left is matched on a line, until that time left == 0. Then whenever the first field ($1) is between 1 and 100 I want to print $1 and if it is left or not. But whatever I try the value of $left is always the same as $1.

    Does anybody know what I'm doing wrong?

    Code:
    $3 ~ /Left/  { left=1 }
    
    $1 >= 1 && $1 <= 100 \
    {
      printf " ""%d"" ""%d"">\n", $1, $left
    }

  2. #2
    and the hat of wrongness Salem's Avatar
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    $left prints $1

    You're thinking of Perl, which has $ in all scalar variable references

    In awk, it's
    printf " ""%d"" ""%d"">\n", $1, left
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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  3. #3
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    ah yes that works, thanks

    I wasnt thinking of perl though since I never used it
    Last edited by KIBO; 01-23-2007 at 07:57 AM.

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