I was given a task where I need to send the address(ex: 0x2add0010) to the firmware in which the lower 6 bits are reserved I need to send the address accordingly.
Could you please tell how to align this one as I got this address when I requested the memory through kmalloc()
Thank you,
I suppose you could do something like this.
Now one element of alignment will have an address where the bottom 6 bits has the pattern you desire.Code:struct alignedmem { char alignment[64]; // for 6 bits char mem[]; // C99 Flexible Array Member }; // then if size is the amount you want to malloc, then do struct alignedmem *mem = kmalloc( sizeof(*mem) + size );
All you then do is pass &mem->alignment[x] to your device.
When you're done, you kfree(mem);
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
The alignment[] array actually only has to be 63 bytes long. If you need to offset by 64 bytes to align, then you're already aligned...Originally Posted by Salem
Code://try //{ if (a) do { f( b); } while(1); else do { f(!b); } while(1); //}
