init adopts zombie process?

This is a discussion on init adopts zombie process? within the Linux Programming forums, part of the Platform Specific Boards category; Hi I tried to create a zombie process with the following program: Code: int main(void) { pid_t pid; int status; ...

  1. #1
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    init adopts zombie process?

    Hi
    I tried to create a zombie process with the following program:
    Code:
    int main(void)
    {
            pid_t pid;
            int status;
    
            if ((pid = fork()) < 0)
                    perror("fork error");
            else if (pid == 0){ /* child process*/
                    exit(0);
            }
            printf("child process ID: %d\n", pid);
            sleep(10);
    
            return 0;
    }
    I can observe the "Z" state with the ps command, but this zombie process (the child process) only exists in the duration from its termination to its parent termination. I don't wait() the child process in the parent, so why doesn't the zombie process exist after the parent terminates?

    In <apue2>,
    But what happens if the parent terminates before the child? The answer is
    that the init process becomes the parent process of any process whose
    parent terminates. We say that the process has been inherited by init. What
    normally happens is that whenever a process terminates, the kernel goes
    through all active processes to see whether the terminating process is the
    parent of any process that still exists.
    My understanding is this: by the time the parent terminates, if there are child processes already terminated and still running, init will adopt the running ones, not the already terminated ones. (don't the "active" and "still exists" in apue2 mean this?) So a zombie child process won't be adopted by init. In my case, by the time the parent terminates, the child is not "active" and won't be adopted by init.

    Besides, the child process in my program disappears immediately after the parent terminates. As I described, I don't think this is done by init, then who did?

  2. #2
    int x = *((int *) NULL); Cactus_Hugger's Avatar
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    All processes, whether running or zombied, are adopted by init when their parent process terminates. init, additionally, will reap any zombie processes.
    long time; /* know C? */
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    Thank you. I got a fully understanding now.

  4. #4
    Captain Crash brewbuck's Avatar
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    Quote Originally Posted by password636 View Post
    My understanding is this: by the time the parent terminates, if there are child processes already terminated and still running, init will adopt the running ones, not the already terminated ones. (don't the "active" and "still exists" in apue2 mean this?) So a zombie child process won't be adopted by init. In my case, by the time the parent terminates, the child is not "active" and won't be adopted by init.
    Why would it behave that way? That would cause zombies to stack up on the system, which is incorrect.

    init adopts ALL processes whose parents have died, whether those processes are still running or not.
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  5. #5
    {Jaxom,Imriel,Liam}'s Dad Kennedy's Avatar
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    As always, there is another way to prevent the zombies. . .

    throw this into your code inside your main control loop (in the parent). . . this is the zombie garbage collection. Leaving zombies while your parent is running is considered to be "bad".
    Code:
    waitpid(-1, NULL, WNOHANG);
    Andy

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