dollar sign is legal in gcc

sourcerer · 02-03-2002, 09:48 PM

hi,

consider this:

#include <iostream.h>

int main()
{
int $one;

cout << $one;
return 0;
}

i've tried this code on bcc 5.5 and it does not compile, but on gcc 2.95 (on linux) it compiles perfectly. why?

Deckard · 02-04-2002, 07:05 AM

GG is correct. The '$' character may not be part of an identifier under ANSI C. You can force gcc to adhere strictly to ANSI C by using the -ansi switch in your compiles. What you lose with the -ansi switch are the keywords asm, inline, and typeof (as well as some macros). The gcc man page has all the details.

02-03-2002, 09:48 PM	#1
sourcerer Registered User Join Date: Feb 2002 Posts: 3	dollar sign is legal in gcc hi, consider this: #include <iostream.h> int main() { int $one; cout << $one; return 0; } i've tried this code on bcc 5.5 and it does not compile, but on gcc 2.95 (on linux) it compiles perfectly. why?
sourcerer is offline

02-04-2002, 07:05 AM	#2
Deckard B26354 Join Date: Jan 2002 Posts: 631	GG is correct. The '$' character may not be part of an identifier under ANSI C. You can force gcc to adhere strictly to ANSI C by using the -ansi switch in your compiles. What you lose with the -ansi switch are the keywords asm, inline, and typeof (as well as some macros). The gcc man page has all the details. __________________ Jason Deckard
Deckard is offline

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