*** pointer madness revisited

moonlord · 08-23-2005, 03:50 AM

let's see the civil war

major_small · 08-23-2005, 04:09 AM

generally, I declare one variable/line, so I declare them like:

Code:

type*var;

but if I'm listing on line line,

Code:

type *var,var,var,*var,var;

and in that line I point out why the other two cases are just wrong.

for the people that want to get into it (I don't): you're not declaring a type of pointer, you're declaring a pointer to a type. the "var" in your example is the pointer, so it should get the '*'. giving the '*' to the type makes it look like you're trying to say that the type is a pointer to a type, when what you really mean to say is that it's a pointer to a type.

and civil wars aren't civil:

Code:

#include<iostream>

int main()
{
	int a,*b,**c,***d,****e;
	b=&a;
	c=&b;
	d=&c;
	e=&d;
	****e=0;
	std::cout<<a<<'\n'<<*b<<'\n'<<**c<<'\n'<<***d<<'\n'<<****e<<std::endl;
	return 0;
}

yeah, I don't know what that had to do with anything, either.

**Salem** · 08-23-2005, 05:55 AM

This was just done - this is pointless.
Difference b/w int* p1 and int *p1

View Poll Results: How do you define pointers?
type* var;	1	20.00%
type *var;	4	80.00%
type * var;	0	0%
another way (please post)	0	0%
Multiple Choice Poll. Voters: 5. You may not vote on this poll

08-23-2005, 03:50 AM	#1
moonlord EOF Join Date: Aug 2005 Location: Constanta, RO, Europe Posts: 46	*** pointer madness revisited let's see the civil war __________________ Two strings walk into a bar. The first one says, 'Bartender! Bartender! I want a drink!'. The second one says, 'Bartender! Bartender! I want a drink too! Blaaaaaaaaah eeeeeeeek yaaaaaaak oooooooh'. The first one says, 'Please excuse my friend. He isn't null term--'.
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08-23-2005, 04:09 AM	#2
major_small Registered User Join Date: May 2003 Posts: 2,787	generally, I declare one variable/line, so I declare them like: Code: typevar; but if I'm listing on line line, Code: type var,var,var,var,var; and in that line I point out why the other two cases are just wrong. for the people that want to get into it (I don't): you're not declaring a type of pointer, you're declaring a pointer to a type. the "var" in your example is the pointer, so it should get the ''. giving the '' to the type makes it look like you're trying to say that the type is a pointer to a type, when what you really mean to say is that it's a pointer to a type. and civil wars aren't civil: Code: #include<iostream> int main() { int a,b,c,d,*e; b=&a; c=&b; d=&c; e=&d; *e=0; std::cout<<a<<'\n'<<b<<'\n'<<c<<'\n'<<d<<'\n'<<*e<<std::endl; return 0; } yeah, I don't know what that had to do with anything, either. __________________ Join is in our Unofficial Cprog IRC channel Server: irc.phoenixradio.org Channel: #Tech Team Cprog Folding@Home: Team #43476 Download it Here Detailed Stats Here More Detailed Stats 52 Members so far, are YOU a member? Current team score: 1223226 (ranked 374 of 45152) The CBoard team is doing better than 99.16% of the other teams** Top 5 Members: Xterria(518175), pianorain(118517), Bennet(64957), JaWiB(55610), alphaoide(44374) Last Updated on: Wed, 30 Aug, 2006 @ 2:30 PM EDT Last edited by major_small; 08-23-2005 at 04:17 AM.
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08-23-2005, 05:55 AM	#3
Salem and the hat of Jobseeking Join Date: Aug 2001 Location: The edge of the known universe Posts: 21,710	This was just done - this is pointless. Difference b/w int* p1 and int *p1 __________________ If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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