Don't forget that some lotteries use a "manual" system to "pick" the numbers. For example a bunch of numbered ping-pong balls in an air chamber popping out numbered balls.
Jim
Don't forget that some lotteries use a "manual" system to "pick" the numbers. For example a bunch of numbered ping-pong balls in an air chamber popping out numbered balls.
Jim
I'm sure it does too but there's no way to know which numbers they will be specifically.
I think the problem can be attacked like this because the TC didn't talk about the abstraction first :
You need to sell tickets to make money
You need to have people win so they still play
Chances of winning grow directly with number of people losing. If the chance of losing is n then the chance of losing m times in a row goes as n^m and because n < 1, n^m gives us an idea of how many tickets we can sell before someone is likely to win.
I'm not sure how what the range on each lottery number is but you can calculate each permutation and its probability. But isn't each permutation given equal probability essentially making this a problem that can only be solved in regards as to when it's likely someone will win the lotto instead of which numbers specifically will win?
If you sell x tickets a day, there's only so many days before it's likely someone wins.
Not directly, no. But given the distribution, you can calculate how probable it is for each number to appear, thereby giving you a guessing chance.Originally Posted by MutantJohn
No, because the probability for each number is not necessarily the same. That is, the chance of losing is actually a function that depends on the numbers you pick.But isn't each permutation given equal probability essentially making this a problem that can only be solved in regards as to when it's likely someone will win the lotto instead of which numbers specifically will win?
Right... I realized that after I posted. Do they even make it publically available what type of number distribution they use for the lotto? You think that'd be the kind of thing they'd keep under wraps.
This software is also self-defeating in the sense that it defeats the purpose of a lotto. The lotto only works because you have a lucky shot at winning. If you guaranteed the outcome, the game would be over so if this software worked, it'd be useful for like a week before there is no more lottery.
Last edited by MutantJohn; 11-25-2014 at 11:47 AM.
I've watched the Michigan lottery and they select the winning numbers from a machine that bounces balls around. Good luck guessing the daily 4 or anything like that, given the circumstances.
I'm pretty sure that each machine (whether mechanical, electrical or electronic) will have passed every test for randomness going (and continues to pass the tests).
Otherwise, the operators would soon find themselves out of business.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Check your post count. You're only a few away from an important milestone.
What can this strange device be?
When I touch it, it gives forth a sound
It's got wires that vibrate and give music
What can this thing be that I found?
Sorry for the long reply, had classes. This code isn't suppose to give exact ticket that will show as the winning number, what it does is to increase probability of achieving the winning ticket. There is a total of about 390M(its a little less just rounding off) that's what the combinations.cpp codes finds for us. The point is to virtually purchase 500M tickets then determine the most commonly repeated tickets since there is only 390M possible tickets so there will be a repetition of over 100M tickets then show the top 100 most likely numbers to be win. Its a long shot but theoretically its a gold mine but time is the enemy here.
How are you purchasing these virtual tickets? Are you just making a ticket structure and assigning random values to it? How are you creating these tickets?
Exactly, what better way to try to pin point a random set then random sets.
I don't think your abstractions are correct.
Under what condition would one number be more likely than another number?
WndProc = (2[b] || !(2[b])) ? SufferNobly : TakeArms;
Lottery winning strategies are a dime a dozen. All are scams, or completely wrong. There is no way to predict a random outcome. Prediction and randomness are opposite concepts.
Your algorithm could only have any hopes of achieving something if it worked out the exact conditions of the initial state of the system where the random numbers will be generated along with the physical events that would subsequently take place. For example, if you could calculate with precision the path of each ball inside the dome before it gets tossed out.
What you are trying to do is to predict a distribution of tickets that could ensure a winning ticket. Assuming you could even have access and buy those tickets with the numbers you predicted, that strategy is so financially ruinous that only complete idiots can consider giving it a try. You will still end up with a bunch of tickets with only a slightly better chance of winning. You will still lose millions of times more than you will win, and your algorithm will just be another piece of junk to add to the other piece of junk algorithms of the people that did it before you. That's right. Many did this already before you. Do you know of anyone winning the lottery because of it?
Originally Posted by brewbuck:
Reimplementing a large system in another language to get a 25% performance boost is nonsense. It would be cheaper to just get a computer which is 25% faster.
(I don't disagree with the rest of your post..but)
Would you tell anyone if you did end up winning a lottery with math?
It would quickly turn into a controversial news.
"Maybe you got lucky?"
"Do you have any connections to the organizers?"
I am not sure if I would.
I'm just gonna close the project for now.
