Thread: Let's talk about Rust!

Apparently not. You can write:

Code:

let x;
x = 1;
print!("{}", x);

the compiler knows that it wasn't used before it was initialized and it will compile and print 1
if you write

Code:

let x;
print!("{}", x);
x = 1;

the compiler will barf at you

Code:

const.rs:3:18: 3:19 error: use of possibly uninitialized variable: `x`
const.rs:3     print!("{}", x);
                            ^
note: in expansion of format_args!
<std macros>:2:23: 2:75 note: expansion site
<std macros>:1:1: 3:2 note: in expansion of print!
const.rs:3:5: 3:21 note: expansion site
error: aborting due to previous error

this can be done because Rust has a loop() so it knows you can only escape via break

Java does the same thing in case of for(;;) and while(true) but not in other cases like while(1 == 1) so it's a little bit embarassing that while(true) and while(1 == 1) don't work the same way