Idea for final project

Originally Posted by std10093

About the char* you said, take a look at the last post here..Read the fgets and atoi part

Yes i agree that for your code, using your own defined π is not a problem.However where you have the problem with the M_PI is not at all visible by me, because you did not post the code where you get the relative error

I get the error if i delete #define PI 3.14159 and then anywhere i have used my defined PI i replace with M_PI it tells me that M_PI has not been defined as a variable. (obviously in my area equations for circle and ellipses)

Which means that these functions do not see the definition i would say...If you want to solve it post the code of it

is it really that hard just to scroll through my code and see what im talking about?

Code:

case 5:                            
{
         printf("\nArea Of A Circle\n");
         printf("\nEnter the radius: ");
         scanf("%lf", &rad1);
         while(rad1 <= 0)
         {
                printf("ERROR!! Distance must be a positive number\n\n");
                printf("Enter the radius: ");
                scanf("%lf", &rad1);
         }
         area = (rad1 * rad1) * PI;
         printf("The area of a circle with a radius of %.4f is %.4f\n\n", rad1, area);
         break;
} 
case 6:
{
         printf("\nArea Of An Ellipse");
         printf("\nEnter radius-1: ");
         scanf("%lf", &rad1);
         while(rad1 <= 0)
         {
                printf("ERROR!! Distance must be a positive number\n\n");
                printf("Enter radius-1: ");
                scanf("%lf", &rad1);
         }
         printf("\nEnter radius-2: ");
         scanf("%lf", &rad2);
         while(rad2 <= 0)
         {
                printf("ERROR!! Distance must be a positive number\n\n");
                printf("Enter radius-2: ");
                scanf("%lf", &rad2);
         }
         area = (rad1 * rad2) * PI;
         printf("The area of an ellipse with a radius-1 of %.4f and a radius-2 of %.4f is %.4f", rad1, rad2, area);
         break;
}

is the only place i use my pre defined PI, but when i add volumes i will use it more. again, this isn't necessarily a problem though as my code works fine without using the M_PI command

I did scroll down your code

M_PI is not a command.It is defined inside the math library.
If you want to use it you have to replace PI with M_PI

Originally Posted by std10093

I did scroll down your code

M_PI is not a command.It is defined inside the math library.
If you want to use it you have to replace PI with M_PI

That is what i've been saying.... i have the math.h header file included and the M_PI does not work... i cant explain this any more clear than i already have.

"error #2048: Undeclared identifier 'M_PI'."

What compiler/OS are you using?
Perhaps try adding this line directly above "#include <math.h>"

Code:

#define _USE_MATH_DEFINES

Originally Posted by friedsandwich

That is what i've been saying.... i have the math.h header file included and the M_PI does not work... i cant explain this any more clear than i already have.

"error #2048: Undeclared identifier 'M_PI'."

how to you compile the program? Do you also include -lm?

I am using Pelles C, I use this because this is the one we use at school.

Originally Posted by Matticus

What compiler/OS are you using?
Perhaps try adding this line directly above "#include <math.h>"

Code:

#define _USE_MATH_DEFINES

this worked.

Maybe on top of the arithmetic your program offers you could add to the functionality with a memory function or 'cancel entry' function in case the user is say adding lots of numbers and makes a mistake with one of the values - you can remove the last one entered

Originally Posted by rogster001

Maybe on top of the arithmetic your program offers you could add to the functionality with a memory function or 'cancel entry' function in case the user is say adding lots of numbers and makes a mistake with one of the values - you can remove the last one entered

hmm... that would be an awesome option, but no idea how to implement that...