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Old 09-30-2009, 02:13 AM   #1
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help with some math problems, introduced in physics class

Hello!

I need some problems solved for physics class which is soon, so I'm taking my chances here. If no one answers before, I still want to learn how it's done
So here we go.

Translation from Danish:

On the motor of a turn-bench it says that it's max horsepower if 2.0 HK. When in use at work it uses 1.2 HK. The work takes 5 minutes.

a. How much Joules does the motor use?
b. How much kWh does the motor use?
c. What's the cost of the energy, when 1 kWh costs 1,50 kr.?


I DO NOT just want answers, I want to learn and learn how it's done So if anyone has the time and feels like helping out, please do so! It WILL be much appreciated!
Thanks in advance!
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Old 09-30-2009, 03:20 AM   #2
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What have done so far?
Anyway here's a clue for solving a) part
1.Find out which physical quantity has Horsepower as its unit.
2.Find out which physical quantity has Joules as its unit.
3.Find out which physical quantity has minutes as its unit!.
4.Find out the formula relating the above three quantities.
5.Substitute for known quantities and find the unknown part.

Hint: Use google if you are stuck in any of the above steps.
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Old 09-30-2009, 03:26 AM   #3
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a.

δE=P∙δt
δE=895∙300
δE=268500 J

b.

kWh=0,895/(5 mins)=(0,895∙12)/(5∙12)=10,74kW/1h=10,74kWh

c.

1 kWh=1,59 kr.
10,74 kWh=1,59∙10,74=17,08kr

---

Is this correct? I had to figure out the algorithms/formulas myself, and some of my class mates ain't getting the same result, they claim to be using some formula told by the teacher, yet I can't see why my result should be wrong.

EDIT: ',' means the same as '.' just that it's opposite in Scandinavia and other countries, 1.8 == 1,8
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Last edited by Akkernight; 09-30-2009 at 03:31 AM.
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Old 09-30-2009, 03:48 AM   #4
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a) part apart from a minor approximation is Ok i think.[746*1.2=895.2~895] But i couldn't make heads or tails of your solution for the b) part(With all that use of ','s and '.'s which is very peculiar to me). Either case, look up here.
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Old 09-30-2009, 08:55 AM   #5
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A quick search found this:
1 horsepower hour = 2684519.5368856 joules
1 hourspower = 0.7456 kilowatts
That should be enough information.
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Old 09-30-2009, 10:43 AM   #6
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How much is 1.2 jigawatts?
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Old 09-30-2009, 10:50 AM   #7
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Quote:
Originally Posted by whiteflags View Post
How much is 1.2 jigawatts?
I thought it was 1.21 gigawatts? Jigawatts don't exist... except maybe in Jay-Z's world.
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Old 09-30-2009, 11:03 AM   #8
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Quote:
Originally Posted by hk_mp5kpdw View Post
I thought it was 1.21 gigawatts? Jigawatts don't exist... except maybe in Jay-Z's world.
When you're powering a magnetic flux capacitor, they're called "jigawatts".
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Old 09-30-2009, 02:24 PM   #9
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Quote:
Originally Posted by whiteflags View Post
How much is 1.2 jigawatts?
Same as the average lightning bolt obviously.
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Old 09-30-2009, 02:37 PM   #10
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Questions a and b are the same thing. Joules and kWh are both units of energy or work. It's just a difference of unit (like feet vs. meters).

If you take a power and multiply it by a time, you get a quantity with units of energy. But to get a meaningful unit, you need to first convert the horsepower to a more standard unit: watts. The time should also be converted to seconds instead of minutes. The product of these two has unit watt-second, which is the same thing as a joule.

To convert from joules to kWh, divide by 3600000.

The third part is simple given the solution to the second part.
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