Help with loading files into rich text box

OK, I followed the Microsoft MSDN and copied their code exactly, and it work for RTF files only, but I want to be able to open text files, html files, php files....basically any files.

The code is:

Code:

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;

namespace WindowsApplication1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void toolStrip1_ItemClicked(object sender, ToolStripItemClickedEventArgs e)
        {

        }

        public void LoadMyFile()
        {
            // Create an OpenFileDialog to request a file to open.
            OpenFileDialog openFile1 = new OpenFileDialog();

            // Initialize the OpenFileDialog to look for RTF files.

            openFile1.Filter = "Text Files|*.txt"; 

            // Determine whether the user selected a file from the OpenFileDialog.
            if (openFile1.ShowDialog() == System.Windows.Forms.DialogResult.OK &&
               openFile1.FileName.Length > 0)
            {
                // Load the contents of the file into the RichTextBox.
                richTextBox1.LoadFile(openFile1.FileName);
            }
        }

        private void openmenu1_Click(object sender, EventArgs e)
        {
            LoadMyFile();
        }
    }
}

I get this error when I double click on the file to open:

"File Format is not valid", and it relates to this code:

Code:

richTextBox1.LoadFile(openFile1.FileName);

.


I am a beginner in C#, and want to understand how it works,


Thanks,

BP

Try

Code:

richTextBox1.LoadFile(openFile1.FileName, RichTextBoxStreamType.PlainText)

OK, thank you. I will try it when I get home

BP

This is how i open files! A good piece of code.

Code:

public void LoadMyFile()
{
	// Create an OpenFileDialog to request a file to open.
	OpenFileDialog openFile1 = new OpenFileDialog();
	// Initialize the OpenFileDialog to look for RTF files.
	openFile1.Filter = "Text Files|*.txt"; 	
	//
	//Try to open the file
	try
	{
		// Determine whether the user selected a file from the OpenFileDialog.
		if (openFile1.ShowDialog() == System.Windows.Forms.DialogResult.OK && openFile1.FileName.Length > 0)
		{
			//Declare using the StreamReader
			using(System.IO.StreamReader Reader = new System.IO.StreamReader(openFile1.FileName))
			{
				//Declare a buffer in which to hold each line and write it to the richTextBox
				string buffer = null;
				//
				//Writing one and one line from the file to the richTextBox
				foreach((buffer = Reader.ReadLine())
					richTextBox1.Text += buffer + System.Environment.NewLine;
			}
		}
	}
	// Run this is file opening fails. It will fail in case of invalid filename and so on
	catch(Exception x)
		MessageBox.Show("Error while opening file:\n\n" + x.Message.ToString());
}

I just wrote it in notepad out of the blue now, so it's not debugged. There might be an error here or there in the line of forgetting the ";" and so on, but you'll figure it out ;-)

Good luck to you!