FindAll Error

Hi,

I'm using FindAll to filter a list of files contained in an array. I get the following error:-
'no overload method FindAll takes 1 arguments', I Presume that I'm missing the argument T[] array from the following definition that pops up in my editor:-

Code:

public List<T> FindAll(T[] array,Predicate<T> match)

However this is not the same as the definition as described
List.FindAll Method (System.Collections.Generic)

Any ideas on how this may be resolved?
Thanks

My code:-

Code:

 files = files.FindAll(delegate(FileInfo f) { return f.Extension.ToLower() == ".c" || f.Extension.ToLower() == ".h"; });

I would, personally, just use a lambda for the predicate:

Code:

            List<string> files = new List<string>(new string[] { "blah.c", "info.txt", "foo.c", "slapmesilly.der", "bar.h" });

            List<string> specificFiles = files.FindAll(f => f.EndsWith(".c") || f.EndsWith(".h"));

            foreach (string file in specificFiles)
                Console.WriteLine(file);

Result:

Code:

blah.c
foo.c
bar.h

Of course, I prefer LINQ, which works on any type that implements IEnumerable<T>. Using the following code you get the same results as above:

Code:

            string[] files = { "blah.c", "info.txt", "foo.c", "slapmesilly.der", "bar.h" };

            foreach (string file in files.Where(f => f.EndsWith(".c") || f.EndsWith(".h")))
                Console.WriteLine(file);