3D array initializer list

kenryuakuma · 10-30-2009, 08:26 AM

Code:

int [,] 2D = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}, {10, 11, 12}};

for two dimensional array, when we look at the initializer list, we can clearly know that what kind of 2 dimensional array it is. According to how the 2D array is outlined, we say it is 4 x 3 2D array. And then to access the value of 1, we would say use indices of 0, 0 and acess value 6, we use 1, 2.

But when it comes to 3D array, I am so confused.
Take this one for example, which I stole it from MSDN.

Code:

int[, ,] array3D = new int[,,] { { { 1, 2, 3 } }, { { 4, 5, 6 } }}

How can we tell what kind of 3D array it is? Is it 1 x 2 x 3 or what? And besides, what are the three indices to use to access the second or third value within the first set or second set of the curly braces? I am stuck and I hope there would be some help.

C_ntua · 10-30-2009, 08:36 AM

edited

C_ntua · 10-30-2009, 08:38 AM

It is a bad example, but it is a 2x1x3 array.
If it was a 1x2x3 it would be

Code:

{{ { 1, 2, 3 } ,  { 4, 5, 6 } }}

Just start from the inside out. Like

Code:

{ { { 1, 2, 3 } }, { { 4, 5, 6 } }}

2xsomething
Then you can tell that each something is a 1x3

Magos · 10-30-2009, 08:39 AM

I'd format it like this, for easier reading:

Code:

			var x = new int[,,]
			{
				//A
				{
					//A.1
					{
						1,2,3,4,
					},
					//A.2
					{
						5,6,7,8,
					},
					//A.3
					{
						9,0,1,2,
					},
				},
				//B
				{
					//B.1
					{
						3,4,5,6,
					},
					//B.2
					{
						7,8,9,0,
					},
					//B.3
					{
						1,2,3,4,
					},
				},
			};

			//Outer (A, B)
			for(var i1 = 0; i1 < 2; i1++)
			{
				//Middle (1, 2, 3)
				for(var i2 = 0; i2 < 3; i2++)
				{
					//Inner
					for(var i3 = 0; i3 < 4; i3++)
					{
						var v = x[i1,i2,i3];
					}
				}
			}

kenryuakuma · 11-01-2009, 08:46 PM

Thanks so much for helping. But one more question.

I assume this is not possible, but I really wanna know if that really works.

Is it possible to initialize and declare a 3d array like this:

int[, ,] array3D = new int[,,] {{{ 1, 2, 3 }}, {{ 4, 5, 6 }, { 8,0,7 }}}

C_ntua · 11-15-2009, 01:40 AM

Quote:

Originally Posted by kenryuakuma

Thanks so much for helping. But one more question.

I assume this is not possible, but I really wanna know if that really works.

Is it possible to initialize and declare a 3d array like this:

int[, ,] array3D = new int[,,] {{{ 1, 2, 3 }}, {{ 4, 5, 6 }, { 8,0,7 }}}

Try it. It shouldn't though. It doesn't have X*Y*Z elements. It is a 2*(1,2)*3.

10-30-2009, 08:26 AM	#1
kenryuakuma Registered User Join Date: Sep 2008 Posts: 62	3D array initializer list Code: int [,] 2D = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}, {10, 11, 12}}; for two dimensional array, when we look at the initializer list, we can clearly know that what kind of 2 dimensional array it is. According to how the 2D array is outlined, we say it is 4 x 3 2D array. And then to access the value of 1, we would say use indices of 0, 0 and acess value 6, we use 1, 2. But when it comes to 3D array, I am so confused. Take this one for example, which I stole it from MSDN. Code: int[, ,] array3D = new int[,,] { { { 1, 2, 3 } }, { { 4, 5, 6 } }} How can we tell what kind of 3D array it is? Is it 1 x 2 x 3 or what? And besides, what are the three indices to use to access the second or third value within the first set or second set of the curly braces? I am stuck and I hope there would be some help.
kenryuakuma is offline

10-30-2009, 08:36 AM	#2
C_ntua Registered User Join Date: Jun 2008 Posts: 1,134	edited Last edited by C_ntua; 10-30-2009 at 08:38 AM.
C_ntua is offline

10-30-2009, 08:38 AM	#3
C_ntua Registered User Join Date: Jun 2008 Posts: 1,134	It is a bad example, but it is a 2x1x3 array. If it was a 1x2x3 it would be Code: {{ { 1, 2, 3 } , { 4, 5, 6 } }} Just start from the inside out. Like Code: { { { 1, 2, 3 } }, { { 4, 5, 6 } }} 2xsomething Then you can tell that each something is a 1x3
C_ntua is offline

11-01-2009, 08:46 PM	#5
kenryuakuma Registered User Join Date: Sep 2008 Posts: 62	Thanks so much for helping. But one more question. I assume this is not possible, but I really wanna know if that really works. Is it possible to initialize and declare a 3d array like this: int[, ,] array3D = new int[,,] {{{ 1, 2, 3 }}, {{ 4, 5, 6 }, { 8,0,7 }}}
kenryuakuma is offline

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