!(1 && !(0 || 1)) Help

If this is true, !(1 && !(0 || 1)) why exactly?
Can anyone explain how this is to be read?

0 || 1
!(0 || 1)
1 && !(0 || 1)
!(1 && !(0 || 1))

actually, go from left to right. parentheses do not change the direction AND operates in, but parentheses can still effect evaluation of either side:

Code:

int * p = 0;
if ( !( p && !( *p || 0 ) ) )
   printf ( "citizen is right: p == %p\n", ( void * )p );

Originally Posted by scope

If this is true, !(1 && !(0 || 1)) why exactly?
Can anyone explain how this is to be read?

!(1 && !(0 || 1))
= !(1 && !(1))
= !(1 && 0)
= !(0)
= 1

But note that, the individual terms are evaluated from left to right.