Lottery game

I'm creating a lottery game that solicits 6 numbers from the user between 1-59 and then generates 6 numbers until they all match. When I compile and run my code it takes the user input fine. However as it runs through i want it to display what number its on and then keep going until it finds a match to the numbers. However when i do run it the code is just a line of long numbers and thats it. Any suggestions?

Code:

#include "stdafx.h"
#include <iostream>
#include <ctime> 
#include <string>
using namespace std;

void getnums(int[]);

int main() 
{ 
	srand((unsigned) time(0));
	const int MAXNUM = 6;
	int count = 1;
	int total = 0;
	int x, n, nums[MAXNUM];
	int lotnums[MAXNUM];
	for(x=0;x<MAXNUM;x++)
	{
		cout << "\nPlease enter number " << x+1 << " : " ;
		cin >> nums[x];
		if ((nums[x] > 59) || (nums[x] < 1))
		{
			cout << "\nThat is not a valid entry." << endl;
			x=x-1;	
		}

	}

getnums(lotnums);

        for (x=0;x<MAXNUM;x++)
			for (n=0;n<MAXNUM;n++)
			if (lotnums[x]==nums[n])
			{
				cout << nums[0] << " " << nums[1] << " " << nums[2] << " " << nums[3] << " " << nums[4] << " " << nums[5] << endl << endl;
				cout << lotnums[0] << " " << lotnums[1] << " " << lotnums[2] << " " << lotnums[3] << " " << lotnums[4] << " " << lotnums[5] << endl << endl;
				cout << "/n/n Congratulations you just won the lotttery. It took " << total << " attempts." << endl << endl;
			}
			else if (lotnums[x]!=nums[n])
			{
				getnums(lotnums);
				total+=count;
				cout << total;
			}
				return 0;
}



void getnums(int lotnums[])
{
	lotnums[0] = 1 + rand() % 59;
	do
		lotnums[1] = 1 + rand() % 59;
	while (lotnums[0] == lotnums[1]);
	do
		lotnums[2] = 1 + rand() % 59;
	while ((lotnums[0] == lotnums[2]) || (lotnums[1] == lotnums[2]));
	do
		lotnums[3] = 1 + rand() % 59;
	while ((lotnums[0] == lotnums[3]) || (lotnums[1] == lotnums[3]) || (lotnums[2] == lotnums[3]));
	do
		lotnums[4] = 1 + rand() % 59;
	while ((lotnums[0] == lotnums[4]) || (lotnums[1] == lotnums[4]) || (lotnums[2] == lotnums[4]) || (lotnums[3] == lotnums[4]));
	do
		lotnums[5] = 1 + rand() % 59;
	while ((lotnums[0] == lotnums[5]) || (lotnums[1] == lotnums[5]) || (lotnums[2] == lotnums[5]) || (lotnums[3] == lotnums[5]) || (lotnums[4] == lotnums[5]));

	return;
}

Your code prints out the lists everytime any number in the first set matches any number in the second set, not when all six are matched.

Edit to add: if you're willing to deal with the STL, then std::set may be just the thing for you.

ok then so how would i make it cout the count and then keep giong until all six numbers match?

So inside your loop all you do is check whether that particular number is a match, so you might do something like numMatched++ when you find a hit. (Make sure you reset numMatched to 0 before you start.)

Then, after all your for loops have run, either numMatched==6, print and be done, or numMatched < 6 in which case you add 1 to total and do it again.