Of course, as I told you: it runs fine because while (yn = 1) assigns 1 to yn every loop cycle.It runs just fine the way it is in my previous post, but it won't exit.
Running the program, even typying in any different number, yn will be changed to 1 again.
You can't rerun the program because you compare (yn == 1) when yn is a char.I set yn = 1 just before the while statement and after the char yn; statement, and it doesn't allow me to rerun the program at all.
A char is interpreted as a character, not a numeric value, so the comparing won't be true when you type in 1.
1: Declare yn as an int or a bool.
2: Compare yn with a char -> (yn == "r")
and of course change the sentence to "Enter 'r' to rerun program: "