Thread: Random Output Numbers

Here is my code:

Code:

#include <cstdlib> 
#include <ctime> 
#include <iostream>
#include <stdio.h>

using namespace std;
void myflush(std::istream& in)
{
    in.clear();
    in.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}

void mypause()
{
    
    myflush(std::cin);
    std::cin.get();
}
int main(void)   
{ 
    srand((unsigned)time(0)); 
    int random_integer; 
    for(int index=0; index<20; index++){ 
        random_integer = (rand()%10)+1; 
        cout << random_integer << endl; 
        mypause();
    } 
}

I want it so this program Outputs 5 Random numbers instead of one number.

so I want 5 Random numbers such as "19, 9, 1, 6, 8" instead of only one Random number.

So. How would I do this?

I'm guessing you mean five at a time before the pause, since you are outputting twenty random numbers? Why doesn't this work?

Code:

    for(int index=0; index<5; index++){
        random_integer = (rand()%10)+1;
        if (index) cout << ", ";
        cout << random_integer;
    }
    cout << endl;
    mypause();
}

Ok. Thanks for your help.