if statement

This is a discussion on if statement within the C++ Programming forums, part of the General Programming Boards category; Hi guys, it's me the newbie again =) I've a new question. Here's a piece of code I copied from ...

  1. #1
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    Question if statement

    Hi guys, it's me the newbie again =) I've a new question. Here's a piece of code I copied from a book:

    Code:
    //This programme shows an example of the AND && expression
    #include <iostream>
    
    
    int main()
    {
        using namespace std;
        
        short number1 = 10;
        char word = 't';
        
        if (number1 == 10 && word == 't')
        cout<< "Both sides of the AND expression are True";
        cin.get();
        return 0;
    }
    It seems that when I didn't end this line of command:
    Code:
    if (number1 == 10 && word == 't')
    with a semi-colon, the whole script can still run and the main function is working. Why is that so ??? Thanks in advance guys

  2. #2
    C++ Witch laserlight's Avatar
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    I suggest reading the book more for the explanation. If you still do not understand read the tutorial on if statements.
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  3. #3
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    That is correct.

    If you indent your code correctly, it becomes more clear:
    Code:
        if (number1 == 10 && word == 't')
           cout<< "Both sides of the AND expression are True";
    If you do this:
    Code:
        if (number1 == 10 && word == 't');
        cout<< "Both sides of the AND expression are True";
    The compiler will happily produce code, but you will ALWAYS get the output from the cout line.

    --
    Mats
    Compilers can produce warnings - make the compiler programmers happy: Use them!
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  4. #4
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    Oh I see...thanks matsp =) You're a real good programmer. Wonder how many years have you been learning C++?

  5. #5
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    Quote Originally Posted by junkeat90 View Post
    Oh I see...thanks matsp =) You're a real good programmer. Wonder how many years have you been learning C++?
    I've been working with C++ for about half a year, but first time I used C was more than 15 years ago, and the above "problem" would be identical in C, only that you wouldn't use cout, but printf to print the text.

    --
    Mats
    Compilers can produce warnings - make the compiler programmers happy: Use them!
    Please don't PM me for help - and no, I don't do help over instant messengers.

  6. #6
    Cat without Hat CornedBee's Avatar
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    char word = 't';
    Is that really what's in the book? If so, beware, because it's misleading: a char stores a single character, not a word in the traditional sense (you need a string for that), nor a machine word (the CPU's "most comfortable" integer type), nor an x86 word (a 16-bit integer).
    All the buzzt!
    CornedBee

    "There is not now, nor has there ever been, nor will there ever be, any programming language in which it is the least bit difficult to write bad code."
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