Loops: The 'any' inquiry

Alright, in this situation I want to take a program that I wrote and modify it so it can take an integers and if any of the numbers are negative, it returns a negative number, but if all the numbers are positive, it returns their average. This is the program I would like to modify:

Code:

/*	This program is a test driver for anyPositiveEOF.
	   Written by: Chubbs1900
	   Date: 12-01-2007
*/
#include <iostream>
using namespace std;

#ifndef TRUE
	#define  TRUE  1
	#define  FALSE 0
#endif

//	Prototype Statements
	bool anyPositiveEOF (void);

int main (void) 
{
//	Statements
	cout << "Enter numbers <EOF> to stop:\n";
	cout << "anyPositiveEOF is: " << anyPositiveEOF () << endl;
	return 0;
}	// main

/*	================= anyPositiveEOF ==================
	Read number series & determine if any are positive.
	   Pre   Nothing
	   Post  Returns true  if any numbers >  0
	         Returns false if all numbers <= 0
*/
bool anyPositiveEOF (void)
{
	bool anyPositive = false;
	int  numIn;
	while ( !anyPositive && (cin >> numIn) )
	    anyPositive = (numIn > 0);
	return anyPositive;
} // anyPositiveEOF

/* Results:
Enter numbers <EOF> to stop:
-1
-2
3
anyPositiveEOF is: 1

Enter numbers <EOF> to stop:
-1
-2
-3
^danyPositiveEOF is: 0
*/

Code:

#ifndef TRUE
	#define  TRUE  1
	#define  FALSE 0
#endif

you don't need that. There is a native "bool" type in C++.

as for how to know if theres any neg #,

Code:

bool anyNegativeNumber = false;

change it to true when you encounter one.
Then

Code:

if (anyNegativeNumber) {
..
}

You don't need the void in parenthesis either for that matter.

Is this just a ported C program? That's the idea I get.

Originally Posted by iMalc

You don't need the void in parenthesis either for that matter.

Correct. C++ and C have different meanings for empty ()'s in a function definition.

AFAIK, () and (void) are the same thing in C++, but not in C.

AFAIK, () and (void) are the same thing in C++, but not in C.

I believe they have the same meaning in C++ and C in a function definition, but not a function prototype.