Can Anyone Help!! This Is Bugging Me

This is a discussion on Can Anyone Help!! This Is Bugging Me within the C++ Programming forums, part of the General Programming Boards category; What's Up everyone, if anyone can help it would be appreciated. My problem with this program (see output at very ...

  1. #1
    Registered User ProgrammingDlux's Avatar
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    Unhappy Can Anyone Help!! This Is Bugging Me

    What's Up everyone, if anyone can help it would be appreciated.

    My problem with this program (see output at very bottom) is that
    I can use it once,and see one person's age, but when i try to input a second or third name after the first time, and press enter, the DOS Window closes on me. What can I do to keep this Program running for as long as I want?




    #include <fstream.h>
    #include <string.h>
    #include <conio.c>

    char response [10]; //not sure what this does (10)


    int main()
    {

    cout << "\n Input the name Christian, Valerie, or Olivia to see their age.\n";
    cin >> response;

    while(strstr(response,"Christian")!=NULL)
    {
    cout << response << " is 20 years old.\n";
    getch();
    return 0;
    }
    while(strstr(response,"Valerie")!=NULL)
    {
    cout << response << " is 15 years old.\n";
    getch();
    return 0;
    }
    while(strstr(response,"Olivia")!=NULL)
    {
    cout << response << " is 8 years old.\n";
    getch();
    return 0;
    }


    return 0;
    }


    /*OUTPUT*************

    Input the name Christian, Valerie, or Olivia to see their age
    Christian (let's say i put this in)
    Christian is 20 years old (this is the output)

  2. #2
    Mayor of Awesometown Govtcheez's Avatar
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    MI
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    Your program's doing exactly what you told it to...

    You input the name.
    The name is Christian, so it does the stuff in the while loop.
    Then, it returns 0 (quits the program).

    I think this'll do more what you want.

    Code:
    #include <fstream.h> //Why are you including this?
    #include <string.h> 
    #include <conio.c> 
    
    char response [10]; //Response is a character array to store the input.
    
    int main() 
    { 
    
    while((response != 'q') && (response != 'Q'))
    {
    cout << "\n Input the name Christian, Valerie, or Olivia to see their age. (q to quit)\n"; 
    cin >> response; 
    
    if(strstr(response,"Christian")!=NULL)  
        cout << response << " is 20 years old.\n"; 
     
    if(strstr(response,"Valerie")!=NULL) 
        cout << response << " is 15 years old.\n"; 
    
    if(strstr(response,"Olivia")!=NULL) 
         cout << response << " is 8 years old.\n"; 
    }
    
    getch();
    return 0; 
    }

  3. #3
    Registered User ProgrammingDlux's Avatar
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    THanks GOVT...very helpful..but i get 1 error message which reads


    " ANSI C++ forbids comparison between pointer and integer"

    In response to :
    while((response != 'q') && (response != 'Q'))

    What might be the solution?

  4. #4
    Fingerstyle Guitarist taylorguitarman's Avatar
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    You need to check only the first letter of the array
    so instead of:
    Code:
    while((response != 'q') && (response != 'Q'))
    you'd do this:
    Code:
    while((response[0] != 'q') && (response[0] != 'Q'))
    Not the best way to do it though (in case someone has a name starting with Q) but it works for your program.

    To make life easy you could use the toupper() or tolower() functions so you don't have to check for both upper and lower case.

    ** You should also initialize response[] because you're using it before you get a value in the while loop.

  5. #5
    Registered User ProgrammingDlux's Avatar
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    Thanks

    Very Very Comprehensive Reply..THanks a lot Taylor..and Govt..you too..I understand this now..Take care

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