That is true. It is a friend. What is your point?In the above operator, whether or not the parameter were references and const or not, it is unable to do anything unless it's a friend.
That is true. It is a friend. What is your point?In the above operator, whether or not the parameter were references and const or not, it is unable to do anything unless it's a friend.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
No matter.