Thread: New to pointers

  1. #1
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    New to pointers

    Hi, I sort of understood pointers, until I went to cplusplus.com and saw this code:

    Code:
    #include <iostream>
    using namespace std;
    
    int main ()
    {
      int firstvalue = 5, secondvalue = 15;
      int * p1, * p2;
    
      p1 = &firstvalue;  // p1 = address of firstvalue
      p2 = &secondvalue; // p2 = address of secondvalue
      *p1 = 10;          // value pointed by p1 = 10
      *p2 = *p1;         // value pointed by p2 = value pointed by p1
      p1 = p2;           // p1 = p2 (value of pointer is copied)
      *p1 = 20;          // value pointed by p1 = 20
      
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
      return 0;
    }
    the output is:

    firstvalue is 10
    secondvalue is 20

    Ok, what I dont understand is why first value is 10 and not 20. I would really appreciate any simple explanation.

    Oh and...Is there something I could think about or remember so that I dont get confused with pointers?

    THANKS

  2. #2
    Kiss the monkey. CodeMonkey's Avatar
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    The value of firstvalue is changed via p1. p1 is not a copy; it actually points to the value.
    "If you tell the truth, you don't have to remember anything"
    -Mark Twain

  3. #3
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    Code:
    #include <iostream>
    using namespace std;
    
    int main ()
    {
      int firstvalue = 5, secondvalue = 15;
      int * p1, * p2;
    
      cout << "begiinging" << endl;
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
      p1 = &firstvalue;  // p1 = address of firstvalue
      p2 = &secondvalue; // p2 = address of secondvalue
    
      cout << "after pointer assignments (nothing)" << endl;
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
      *p1 = 10;          // value pointed by p1 = 10
    
      cout << "firstvalue changes" << endl;
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
    
      *p2 = *p1;         // value pointed by p2 = value pointed by p1
    
      cout << "secondvalue changes" << endl;
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
    
      p1 = p2;           // p1 = p2 (value of pointer is copied)
    
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
      *p1 = 20;          // value pointed by p1 = 20
      
      cout << "secondvalue changes" << endl;
      cout << "firstvalue is " << firstvalue << endl;
      cout << "secondvalue is " << secondvalue << endl;
    
      return 0;
    }
    Quote Originally Posted by Tesnik View Post
    Oh and...Is there something I could think about or remember so that I dont get confused with pointers?
    bunnies
    THANKS
    you're welcome

  4. #4
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    I dont see why *p1 = 20 makes second value change. p1 is the reference to the firstvalue, so why does secondvalue change and not the firstvalue.

    ive tried with the bunnies... they dont work.

  5. #5
    Deathray Engineer MacGyver's Avatar
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    For now you have this:

    Code:
    p1 ----> firstvalue
    p2 -----> secondvalue
    Code:
    p1 = p2;           // p1 = p2 (value of pointer is copied)
    Now you have this:

    Code:
    firstvalue
    
    p1 --------------> secondvalue <------------- p2
    The first one makes p1 equal to p2. This means they both point to secondvalue.

    Code:
    *p1 = 20;          // value pointed by p1 = 20
    Now you take whatever p1 points to, which is secondvalue, and change it to 20.

    Make sense now?

  6. #6
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    yes!

    thanks very much

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