Converting an integer into a string

Hello, I am trying to save a number of files with the filename format: "image#.bmp", where # is some number between 0 and 1024. I do not know how to get the number in there in a generic way, though.

I know that there is a strtol routine in C, is there anything like the reverse, some simple way of converting an integer (like 72, 5551, 132) to a string? Using either C routines or (preferably) the C++ String class.

Thank you in advance. I'm sure this is a somewhat common question.

I prefer to use sprintf() to do this, e.g.
[code
sprintf(filename, "image%04d.bmp", imgno);
[/code]

Using %04d will make the number look like 0001, 0012, 0123 or 1234 - so all the files come in numerical order if you list them by name (otherwise image9.bmp gets way down past image1xxx, image2xx, etc).

--
Mats

You can use stringstreams to do this which is basically an object-oriented (C++) way of doing the same thing as the sprintf function.

Code:

#include <sstream>
#include <iomanip>
#include <string>
#include <fstream>
using namespace std;

...

for( int i = 1; i <= 1024; ++i )
{
    stringstream sstr;
    sstr << "image" << setw(4) << setfill('0') << i << ".bmp";    // sstr = "image#.bmp" where # is [1..1024]
    ofstream out(sstr.str().c_str());                             // Open file "image#.bmp" for writing
    ...
    // Do stuff with the file here
    ...
    out.close();
}

Same provisions provided above that matsp mentioned about formating the numerical values as 0001, 0002, etc...

Thank you both - I've got it solved (I used the sprintf version, but I'll move to stream version soon).