shared pointer

This is a discussion on shared pointer within the C++ Programming forums, part of the General Programming Boards category; This is the error i get. : error C2440: 'return' : cannot convert from 'class SharedPtr<class TrackableObject> *const ' to ...

  1. #1
    Unregistered
    Guest

    shared pointer

    This is the error i get.
    : error C2440: 'return' : cannot convert from 'class SharedPtr<class TrackableObject> *const ' to 'class TrackableObject &'
    This is the code.
    /**
    * This operator will return a refernce to the SharedPtrImpl object.
    * This function will allow for intuitive use of the operator to be used
    * to access
    * our pointer objects. It will return a reference to the SharedPtrImpl
    * object.
    * @return TYPE reference to an object of type TYPE
    */
    TYPE & operator*(void) const
    {
    return this;
    }
    Ive tried returning: &this, *this.
    Any help would be appreciated.

  2. #2
    S­énior Member
    Join Date
    Jan 2002
    Posts
    982
    TYPE & in the context you've used it is a reference to a TYPE . If you want to return a pointer it should be TYPE*.

  3. #3
    Unregistered
    Guest

    Talking

    Thank you sir.

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