struct ListElement
{
RECT arect;
ListElement* pNextListElement;
};
SOmeone please explain this? Also, why would an object in this struct be the type of RECT which is a different structure? Also, what does the pointer pointing to this struct do here? How does this work and why?
from your title i see u're working on the linked list...
an educated guess.... the code that you posted stands for a so called "Node", which ties the linked list together...
to make the long story short.... think of it this ....
--- bunch of such "struct" each containing similar attributes...(an object and a pointer to another node)
--- think of a "Railroad" .... Railraod track and and your Stations are your "linked lists" ... the tracks "link" to your stations (NODES) ... in your stations "NODES" you can have a BAGEL STORE (your object of another class).... or even more or different type of data...(Burger King)....
hope this short analogy helps....
Regards,
matheo917
Basically, this code is the base for a linked list of RECT's, whatever they might be. Therefore, every single item in the list will each have the properties of a RECT.
The pointer is currently pointing to nothing. However, if you were making a linked list, it would eventually point to a new(on free store) ListElement
By the way, when thinking of linked lists, think of them as the following. Each object is created inside the previous object and the previous object is needed. So instead of being like this
head----->item 1----->item 2---->and so on
think of it as this
Code:\ head /
\ item 1 /
\ item 2 /
When I think of them this way, it helps me out much more then of just simply considering them to be objects pointing to other objects.
I hope this helps u and good luck. :)
Have a look here: http://www.doc.ic.ac.uk/~wjk/C++Intr...erL7.html#S7-5 It explains in a good way how linked lists work and has got illustrations. This site helped me to understand the concept.
Seron