Whats a Pointer

[noobcpp]

Thanks To All Today I've understood properly whats Pointer. I was little bit confused about it before

Today I've Understood Compleately Whats Pointer
"Pointer Is a Special Type Of Variable"
First lets Discuss about Some General Variables
		int var = 50;
Here a Memory address Say 0xbf45d2c5 has been Alloted for this variable.
And in that Location a int Value has been Stored thats 50
and Thats All Now Lets Come To pointer
		int *pVar;
		*pVar = var;
"pVar Points to var" Here pVar is a Pointer Variable
And value of pVar is the Address of teh Variable named var


   (var name)pVar				    (var name)var	
---------------------				---------------------
| (value)0xb7d58bf1 | 			        |     (value) 50    | 
---------------------				---------------------	
(address) 0x4cf8a7d2e				(address) 0xb7d58bf1

So pVar is like a tree it holds another variable's Address and that variable
holds the value . So how Would we get the value under the pVar 
(Thats at teh End of the Tree) So as the Value is on depth 1 we need to use
		cout<<*pVar
To get teh value of var from pVar Directly So we can call * as a direct access 
to value Operator or Syntax for this time just to understand Correctly.
If pVar Points/holds another pointer variable names say mVar and mVar Points/holds 
the variable then we need to use
		cout<<**pVar
To get the value of var from pvar Directly as teh depth is now 2. If we use *pVar
It will just print the Address of var . As the value of mVar is teh Address of var.

Am I right ??

[Salem]

An illustration of the relationship between & and * when referring to a pointer variable.

#include <iostream>
using namespace std;

int main( void ) {
    int var = 1234;
    int *pVar = &var;
    cout << reinterpret_cast<void*>(&pVar) << endl;
    cout << reinterpret_cast<void*>(pVar) << endl;
    cout << *pVar << endl;
    return 0;
}


 Address  Contents
         +--------+
0x22cce0 |0x22cce4| pVar
         +--------+
0x22cce4 |  1234  | var
         +--------+

[noobcpp]

So was I right ??

[Salem]

Barring a few syntactic problems, your explanation seems OK.

Though 'pointer to pointer to' is more akin to a list rather than a tree.

[noobcpp]

K Thanks
But Whats
reinterpret_cast<void*>