Reversing (char)...

I'm not sure if this is possible, but is it possible to reverse the "(char)" function?
For example:

Code:

(char)97 == a

//but I want to do

a == 97

First off, (char) is what is called a C-style cast, it's not called a function, but that's not too important in answering the question i suppose...

What's more important is that you realise what casting is, and how it is performed.

Short answer is that yes you can... depending on the types. If 'a' is a char, you can compare it to an integer - in that particular case you don't even need the (char) in font of it, the compiler understands what you're doing - this is called an implicit cast and the other one is called an explicit cast.

Some short examples of C-style casts

Thanks, Richie!

just in the first sample 97 will be cast to char and compared to a
in the second - a will be cast to int and compared to 97

In most cases it will show no difference, but in some - it can... For example comparing to 255 when the char is signed will bring different results...

Okay, so I understand it now but how do you do string to char and vise versa?

Originally Posted by yaya

Okay, so I understand it now but how do you do string to char and vise versa?

A (C-style) string is a sequence of characters terminated by and including the first null character.

Given that, what are you asking?

It doesn't seem to work with strings.
For example:

Code:

float a=1.1;
cout<<(int)a;

This displays '1' as it should but when I do this:

Code:

string a=("a");
cout<<(char)a;

it comes up with errors. Am I doing something wrong?

Of cource you are. A string object is an object with many member variables and a string representation consisting of two characters, a and \0. How would you cast this whole thing to a 1-byte variable?
I guess what you want to do is

Code:

string a = "a";
cout << a[0];