characters, to many in contsant?

[hudy23]

I am trying to run a program wiht characters and an else if ladder,
this is what i tried to run and it gave me an error of too many characters in constant.
What is wrong with it?
p.s. i am a new programmer, be gentle.


#include <iostream.h>
int main ()
{
char name;
cout<<"Enter your name:";
cin>>clas;

if (name == 'luke')
cout<<"hello"<<endl;
return 0;
}

[Unregistered]

my fault the program should look like this
#include <iostream.h>
int main ()
{
char name;
cout<<"Enter your name:";
cin>>name;

if (name == 'luke')
cout<<"hello"<<endl;
return 0;
}

[Josho]

A char can only be a single character, say 'a' or '5'.
For that program, use a string, which you could think of as simply a sequence of char's, such as luke.

To use strings (I use MS Visual, I don't know about other compilers), you #include <string>, and also add in 'using namespace std', without the 's before your program starts.
The type is string, and for assignment, equality, and whatever else, you use double quotes. Hope this helps.

[johnnie2]

You can also read lesson 9 (character arrays and strings) here on the site.