Is it possible to pass an array to a function?

[Loic]

Is it possible to pass an array to a function?

For example, I am trying to make a function called displaycards, which will display some cards, but I want it to display the cards from a deck which I have in an array in my “int main()” part of the program.

[Dave_Sinkula]

Yes.

Can you post the code related to your attempt?

[Loic]

Some thing like this...

#include <cstdlib>
#include <iostream>

using namespace std;

void displayCards();

int main(int argc, char *argv[])
{
    string Spade[13] = {"A", "2", "3", "4", "5" ,"6", "7", "8", "9", "10", "J", "Q", "K"};
    random_shuffle(Spade, Spade + 13);
        
    cout << "Player 1: \n";
    displayCards();
    
}

void displayCards()
{
     for (int i=0; i<=13; i++)
     { cout << "S: "; spade[i]); }
}

[Dave_Sinkula]

The function displayCards should receive arguments -- generally speaking, the start of the array and its size. And C and C++ are case sensitive.

[Loic]

The function displayCards should receive arguments -- generally speaking, the start of the array and its size. And C and C++ are case sensitive.

Sorry you lost me?

[nadroj]

basically, edit the function (and the prototype, of course) so that it takes two arguments: an array of type string, and an integer, to specify the length of the array.

hope it helps.

[Loic]

basically, edit the function (and the prototype, of course) so that it takes two arguments: an array of type string, and an integer, to specify the length of the array.

hope it helps.

something like this?

#include <cstdlib>
#include <iostream>

using namespace std;

void displayCards(string, int);

int main(int argc, char *argv[])
{
    string Spade[13] = {"A", "2", "3", "4", "5" ,"6", "7", "8", "9", "10", "J", "Q", "K"};
    random_shuffle(Spade, Spade + 13);
        
    cout << "Player 1: \n";
    displayCards(Spade, 13);
    
}

void displayCards(string Spade, int i)
{
     for (int i=0; i<=13; i++)
     cout << "S: "; Spade[i]);
}

[nadroj]

almost.. with that code the function takes in a single string.. you want a string array.

[Loic]

almost.. with that code the function takes in a single string.. you want a string array.

Ok, so i have this.

void displayCards(string array, int);

int main(int argc, char *argv[])
{
    string Spade[13] = {"A", "2", "3", "4", "5" ,"6", "7", "8", "9", "10", "J", "Q", "K"};
    random_shuffle(Spade, Spade + 13);
        
    cout << "Player 1: \n";
    displayCards(Spade, 13);
    
}

void displayCards(string array Spade, int i)
{
     for (int i=0; i<=13; i++)
     cout << "S: "; Spade[i]);
}

but i get this error? " conversion from `std::string*' to non-scalar type `std::string' requested "

sorry if i am being a pain, i tried to look all this up on google, but that just confused me even more... lol

[nadroj]

you know how to declare a string array, you did it in main! whats this 'array' keyword nonsense!

KISS! its no different!

edit: also, in your cout statement in the displayCards function remove the ')' and change the middle ';' to '<<'

[Loic]

you know how to declare a string array, you did it in main! whats this 'array' keyword nonsense!

KISS! its no different!

edit: also, in your cout statement in the displayCards function remove the ')' and change the middle ';' to '<<'

ok, so so far i have this

#include <cstdlib>
#include <iostream>

using namespace std;

void displayCards(string Spade);

int main(int argc, char *argv[])
{
    string Spade[13] = {"A", "2", "3", "4", "5" ,"6", "7", "8", "9", "10", "J", "Q", "K"};
    random_shuffle(Spade, Spade + 13);
        
    cout << "Player 1: \n";
    displayCards(Spade[0,13]);
    system("pause");
    return EXIT_SUCCESS;
}

void displayCards(string Spade)
{
     for (int i=0; i<=13; i++)
     {
         cout << "S: " << Spade[i];
     }
}

it compiles fine, but when i run it i get this.

This application has requested the Runtime to terminate it in an unusual way.
Please contact the application's support team for more information.

[nadroj]

ok, i think ive tortured you enough...

to declare your array of strings, you did:

string Spade[13]

string[] is the datatype--that is, its a 'string array'. in your function and prototype, append '[]' to the datatype:

void displayCards(string[] Spade);

also, i would recommend using lower-case variable names (ie 'spade' not 'Spade') and camel-casing when necessary, as you have ('displayCards'). when i see a capital i think its a class name. my two cents.

[Daved]

Even

void displayCards(string Spade[13]);

would work. It's the same, you are declaring an array of strings, its just that this one is also a parameter to the function.

One other issue, you should be using < instead of <=. When i = 13, it is out of bounds of a 13 element array (valid indexes are 0 - 12).

[Loic]

ok, i think ive tortured you enough...

to declare your array of strings, you did:

string Spade[13]

string[] is the datatype--that is, its a 'string array'. in your function and prototype, append '[]' to the datatype:

void displayCards(string[] Spade);

also, i would recommend using lower-case variable names (ie 'spade' not 'Spade') and camel-casing when necessary, as you have ('displayCards'). when i see a capital i think its a class name. my two cents.

ok now i am really ripping my hair out!!!!

void displayCards(string[]);

int main(int argc, char *argv[])
{
    string spade[13] = {"A", "2", "3", "4", "5" ,"6", "7", "8", "9", "10", "J", "Q", "K"};
    random_shuffle(spade, spade + 13);
        
    cout << "Player 1: \n";
    displayCards(spade[0,13]);
    system("pause");
    return EXIT_SUCCESS;
}

void displayCards(string[13] spade)
{
     for (int i=0; i<13; i++)
         cout << "S: " << spade[i];
}

i get this message from the compiler

cannot convert `std::string' to `std::string*' for argument `1' to `void displayCards(std::string*)'

[MacGyver]

You're making up syntax here.

What is this?

displayCards(spade[0,13]);

Should be this:

displayCards(spade);