Thread: Array of Streams

Hello, this is my first post here.

I am a novice C++ programmer, and I've come upon a problem that I don't know how to solve. What I'm trying to do is send some output first to cout and then to a file. The obvious way to do this would be something like:

Code:

#include "iostream"
#include "fstream"
...
	ofstream Log("./Log");
	cout << "Some text." << endl;
	Log << "Some text." << endl;
	Log.close();
...

However, if "Some text" is a whole bunch of output then this is a lot of code duplication. What I'd like to do is define an array of streams that has 2 elements. The first is cout and the second is my file stream. Then I'd have a loop over this stream array, and write the same stuff to each stream.

But I can't quite get it to work. The best I've been able to come up with (after some scanning of the internet) is this:

Code:

#include "iostream"
#include "fstream"
...
	ofstream Log("./Log");
	ostream s[2];
	s[0].rdbuf(cout.rdbuf());
	s[1].rdbuf(Log.rdbuf());

	int i;
	for(i=0; i<2; i++){
		s[i] << "Some text." << endl;
		s[i] << "Some more text." << endl;
	}
...

This almost works. It sends everything to cout just as it should, but it chokes at the first "endl" when sending to my file, so that the file simply contains "Some text.".

What am I doing wrong, and is there a more elegant way of accomplishing this?

Thanks very much for any and all help.

Originally Posted by Oysterman

This works, although it may look clumsy and undecipherable to a novice. It's how I'd do it, for better or worse.

I understood it perfectly well, and it works fine when I adapt it into my code. Problem solved.

Thanks very much!