Thread: Bit of help required still - using a function with array

Sorry I pasted an earlier code before fixing it, this one compiles but I can't figure out how to make the values go through my function, or if I made it correctly to change input from user into celsius.

Code:

// Computer Lab test.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
using namespace std;

double c;
double celsius;
double CheckCent(double c)
{
    if ( c>30 )
    {
        return 1.8 * celsius + 32;
    }
	return c;
}


// call this function to convert celsius to fahrenheit (function name is convert)
int _tmain(int argc, _TCHAR* argv[])
{
double myarray[51];
//double i;
int flag;
flag=1;
int i;
for(i = 0; i < 51 && flag == 1; i++)
{   // Loop to enter temperatures - pressing 1 continues, pressing 0 stops //
	cout << "Enter Temperature Reading:";
	cin >>myarray[i];
	cout << "Enter 1 to input more values, 0 to stop";
	cin >>flag;
}// End for
cout << "Number of elements in the array is: " << i;
cout <<"\n";

		return 0;
}

So apart from not compiling, what do you want us to do with than unindented mess?

> if ( c>30 )
And what do you return if it's <= 30?
The maths works on all values, so why bother with this condition.

You didn't fix the lack of indentation with your edit.

Basically the same question here as well
http://cboard.cprogramming.com/showthread.php?t=88246
Closed (& read the rules)