Thread: Binary Representation of String

Do you know how to do it for a single character? If so, then just do that for each character in the string.

If not . . .

You can use

Code:

number & 1

to get the value of the rightmost bit. Then you can use

Code:

number >>= 1

to shift the bits to the right. But using that method will generate the bits in reverse order. If you know how many bits there are (ie, 8), then it might be better to use

Code:

mask = UCHAR_MAX;
n = 7;
loop
    number & mask >> n;
    mask /= 2
    n --

or something.

Also note that the MSB (rightmost digit) will probably be 1 for negative numbers, depending on your compiler's implementation.

Also see this (somewhat advanced) FAQ: http://faq.cprogramming.com/cgi-bin/...&id=1044780608

Exactly. (Except that you can't have a variable called char. )

Then you can use

Code:

variable = variable >> 1;

to eliminate the LSB, shifting all of the bits to the right.

The bitset idea looks really good.