Thread: Forbids Declaration of '___' with no type

  1. #1
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    Forbids Declaration of '___' with no type

    I'm getting this error, "Forbids Declaration of '___' with no type", for just about every function I have in my class and I have no idea what's wrong. Can any of you help me understand what's happening? I can elaborate more if needed.

  2. #2
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    It's also telling me that a few of my operators can not be overloaded. I'm just declaring them like this:

    Code:
    Object operator[](int);

  3. #3
    Officially An Architect brewbuck's Avatar
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    Quote Originally Posted by warfang View Post
    I'm getting this error, "Forbids Declaration of '___' with no type", for just about every function I have in my class and I have no idea what's wrong. Can any of you help me understand what's happening? I can elaborate more if needed.
    Have you specified the return value types of all your methods? You can't leave that out. If a method returns nothing, it must be declared return type "void."

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    In my header file:

    Code:
    int & operator[](int);
    In my .cpp file:

    Code:
    Object::operator[](int index){
        ....
        return &temp[0][0];
    }
    And that's how I have it set up.

  5. #5
    carry on JaWiB's Avatar
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    two things:
    Code:
    int & Object::operator[](int index){
    //...
    }
    Also, you're returning a pointer, when you should be returning a reference (the compiler will complain when you fix the other errors).
    "Think not but that I know these things; or think
    I know them not: not therefore am I short
    Of knowing what I ought."
    -John Milton, Paradise Regained (1671)

    "Work hard and it might happen."
    -XSquared

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    I don't get it. In the header I already stated what it was going to return. So I have to do it in both files?

  7. #7
    Hurry Slowly vart's Avatar
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    Quote Originally Posted by warfang View Post
    I don't get it. In the header I already stated what it was going to return. So I have to do it in both files?
    yes - declaration should exactly match the definition of the function...
    The only thing you can skip in declaration - is var names, the rest - return type and var types should be the same
    All problems in computer science can be solved by another level of indirection,
    except for the problem of too many layers of indirection.
    – David J. Wheeler

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