How to use pointers in this case?

This is a discussion on How to use pointers in this case? within the C++ Programming forums, part of the General Programming Boards category; I have the following code Code: #include <stdio.h> typedef struct { char nume[60]; char sectie[20]; int grupa; } student; int ...

  1. #1
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    Jan 2007
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    Question How to use pointers in this case?

    I have the following code
    Code:
    #include <stdio.h>
    
    typedef struct
    {
    	char nume[60];
    	char sectie[20];
    	int grupa;
    } student;
    
    int schimb (student *faculta)
    {
      faculta[1]->grupa=6;
    return 0;}
    
    int main()
    {student faculta[3];
      faculta[1].grupa=5;
      schimb(&faculta[1]);
      printf("%d",faculta[1].grupa);
    return 0;}
    the code shell only change the value of faculta[1].grupa using the function schimb.
    How can I make this code work ?

  2. #2
    The superhaterodyne twomers's Avatar
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    Ireland
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    Code:
    #include <stdio.h>
    
    typedef struct 
    {
    	char nume[60];
    	char sectie[20];
    	int grupa;
    } student;
    
    void schimb (student *faculta)
    {
    	faculta->grupa = 6;
    }
    
    int main( void )
    {
    	student faculta[3];
    
    	faculta[1].grupa=5;
    
    	
    	printf("Before: %d\n",faculta[1].grupa);
    	schimb(&faculta[1]);
    	printf("After:  %d\n",faculta[1].grupa);
    
    	return 0;
    }
    What you passed into the function was one value of the array. Not an array in itself. I also did some formatting ... makes it look nicer.

  3. #3
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    How can I make this code work ?
    What do you want to do?

  4. #4
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    Quote Originally Posted by 7stud
    What do you want to do?
    Ok and how do I pass into the function the whole array and not only a value of the array ?

  5. #5
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    Code:
    void display( int arr[], int length)
    {
    	for(int i = 0; i < length; ++i)
    	{
    		cout<<arr[i]<<" ";
    	}
    	
    	cout<<endl;
    }
    
    
    int main()
    {
    	const int SIZE = 3;
    	int myArray[SIZE] = {10, 20, 30};
    	display(myArray, SIZE);
    
            return 0;
    }
    Last edited by 7stud; 01-14-2007 at 08:23 PM.

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