any one plz help me

This is a discussion on any one plz help me within the C++ Programming forums, part of the General Programming Boards category; Here's another hint: think of how you do addition by hand. You would add one column of digits, carrying over ...

  1. #16
    C++ Witch laserlight's Avatar
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    Here's another hint: think of how you do addition by hand. You would add one column of digits, carrying over if needed.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  2. #17
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    ya i know i have to solve it like that but i cant understand how to right that code

  3. #18
    The superhaterodyne twomers's Avatar
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    Try. Fail. Post code. We might fix it for you or tell you how to.

  4. #19
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    b quick buddies and i have one two more probs with my assignment acctually i have to calculate zakat of 500.98gram gold(24 carat)
    and 2) how can i assign an array to another

  5. #20
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    You need to at least have a go yourself first. You can't just expect people to write the code for you.

    Even if you're way off, have a go, post what you've done, then maybe you'll get some help.

  6. #21
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    and buddies what is that meaning e.d
    a^b
    how does it works"^"

  7. #22
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    ya i have tried all of them by my self but failed

  8. #23
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    Post your efforts.

  9. #24
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    Code:
    #include<stdio.h>
    #include<conio.h>
    #define MAXDIGITS 100
    ch_to_bignum(char *s,bignum *n);
    main()
    {
    clrscr();
    typedef struct {
    		char digits[MAXDIGITS],
    		int signbit,
    		int lastdigit,
    		}bignum;
          digits m1,m2;
    printf("enter digits");
    scanf("%c",m1);
    printf("enter 2nd digit");
    scanf("%c",m2);
    ch_to_bignum(char*s,bignum*n);
    getch();
    }
    
    ch_to_bignum(char*s,bignum*n)
    {
    int i;
    if(s[0]!='-'
    {
    n->signbit='PLUS'
    i=0;}
    else
    {i=1;
    n->signbit='MINUS'
    }
    strcpy(n->digits,&s[i])
    n->lastdigit=strlen(n->digits)
    }

  10. #25
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    now i have to calculate 11111111111111111111111111111000000000000000000000 00000000000023333333333+45345789999999999999999992 43214444444444444444444444444444444444444440333333 3333333 as well as"-" and "*"

  11. #26
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    Quote Originally Posted by twomers
    Try. Fail. Post code. We might fix it for you or tell you how to.

    ok i will try my best but give me some hints that how can i add long ints by taking carry

  12. #27
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    Code:
    #include<stdio.h>
    #include<conio.h>
    #include<stdlib.h>
    #include<string.h>
    
    main()
    {
    clrscr();
    int a[500];
    int b[500];
    int num1,num2,x,y,i,j,sum;
    printf("input numbers");
    scanf("%d",&a);
    printf("input 2nd numbers");
    scanf("%d",&b);
    num1=atoi(a);
    num2=atoi(b);
    printf("num1 =%d",num1);
    printf("num2 =%d",num2);
    x=strlen(a);
    y=strlen(b);
    {
    for(i=x;i>=0;i--)
    printf("\n%d",a[i]);
    }
    for(j=y;j>=0;j--)
    {
    printf("\n%d",b[j]);
    }
    sum=a[i]+b[j];
    printf("sum=%d",sum);
    getch();
    }
    this is not complete

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