any one plz help me

This is a discussion on any one plz help me within the C++ Programming forums, part of the General Programming Boards category; Here's another hint: think of how you do addition by hand. You would add one column of digits, carrying over ...

  1. #16
    C++ Witch laserlight's Avatar
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    Here's another hint: think of how you do addition by hand. You would add one column of digits, carrying over if needed.
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  2. #17
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    ya i know i have to solve it like that but i cant understand how to right that code

  3. #18
    The superhaterodyne twomers's Avatar
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    Try. Fail. Post code. We might fix it for you or tell you how to.

  4. #19
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    b quick buddies and i have one two more probs with my assignment acctually i have to calculate zakat of 500.98gram gold(24 carat)
    and 2) how can i assign an array to another

  5. #20
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    You need to at least have a go yourself first. You can't just expect people to write the code for you.

    Even if you're way off, have a go, post what you've done, then maybe you'll get some help.

  6. #21
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    and buddies what is that meaning e.d
    a^b
    how does it works"^"

  7. #22
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    ya i have tried all of them by my self but failed

  8. #23
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    Post your efforts.

  9. #24
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    Code:
    #include<stdio.h>
    #include<conio.h>
    #define MAXDIGITS 100
    ch_to_bignum(char *s,bignum *n);
    main()
    {
    clrscr();
    typedef struct {
    		char digits[MAXDIGITS],
    		int signbit,
    		int lastdigit,
    		}bignum;
          digits m1,m2;
    printf("enter digits");
    scanf("%c",m1);
    printf("enter 2nd digit");
    scanf("%c",m2);
    ch_to_bignum(char*s,bignum*n);
    getch();
    }
    
    ch_to_bignum(char*s,bignum*n)
    {
    int i;
    if(s[0]!='-'
    {
    n->signbit='PLUS'
    i=0;}
    else
    {i=1;
    n->signbit='MINUS'
    }
    strcpy(n->digits,&s[i])
    n->lastdigit=strlen(n->digits)
    }

  10. #25
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    now i have to calculate 11111111111111111111111111111000000000000000000000 00000000000023333333333+45345789999999999999999992 43214444444444444444444444444444444444444440333333 3333333 as well as"-" and "*"

  11. #26
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    Quote Originally Posted by twomers
    Try. Fail. Post code. We might fix it for you or tell you how to.

    ok i will try my best but give me some hints that how can i add long ints by taking carry

  12. #27
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    Code:
    #include<stdio.h>
    #include<conio.h>
    #include<stdlib.h>
    #include<string.h>
    
    main()
    {
    clrscr();
    int a[500];
    int b[500];
    int num1,num2,x,y,i,j,sum;
    printf("input numbers");
    scanf("%d",&a);
    printf("input 2nd numbers");
    scanf("%d",&b);
    num1=atoi(a);
    num2=atoi(b);
    printf("num1 =%d",num1);
    printf("num2 =%d",num2);
    x=strlen(a);
    y=strlen(b);
    {
    for(i=x;i>=0;i--)
    printf("\n%d",a[i]);
    }
    for(j=y;j>=0;j--)
    {
    printf("\n%d",b[j]);
    }
    sum=a[i]+b[j];
    printf("sum=%d",sum);
    getch();
    }
    this is not complete

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