Thread: dynamically declaring variables

Code:

#include<iostream>
using namespace std;

class Whatever
{
  public:  
  stuff( );
};

int main()
{
    int x=0,
        y=0;

    cout << "Enter a number: " ;
    cin >> x ;

    cout << "\nEnter another number: " ;
    cin >> y ;

    Whatever myWhatever[x][y] ;

    //as an added extra bonus:
    for(int i=0; i<x; i++)
       for(int j=0; j<y; j++)

           cout << myWhatever[i][j].stuff() ;

return 0 ;
}

@The Brain: I guess what smartalco wanted was *naming* variable with the pattern 'name<x><y>' which is impossible I think. Besides, your code cannot even compile, you would need to use dynamic memory allocation to allocate an array with a variable size.

oops..

Code:

#include<iostream>
using namespace std;

class Whatever
{
  public:  
  stuff( );
};

int main()
{
    int x=0,
        y=0;

    cout << "Enter a number: " ;
    cin >> x ;

    cout << "\nEnter another number: " ;
    cin >> y ;

    Whatever **myWhatever = new Whatever*[x] ;
    for(int i=0; i<x; i++)
        myWhatever[i] = new Whatever[y] ;

    //as an added extra bonus:
    for(int i=0; i<x; i++)
       for(int j=0; j<y; j++)

           cout << myWhatever[i][j]->stuff() ;

return 0 ;
}

Yes, the code itself cannot reflect some variable factor. That would make for some very strange possibilities, wouldn't it? But yes, Tonto's suggestion is the best idea if you are looking to associate some variable with two values. Say you wanted to simulate integers with dynamic names:

Code:

std::srand(std::time(NULL));
int x, y;
int val;
std::stringstream name;
std:map<std::string,int> variables;
for(int loop = 0; loop < num_of_vars; loop++)
{
   x = std::rand();
   y = std::rand();
   name << "whatever<" << x << "><" << y << '>';
   cin >> val;
   variables[name.str()] = val;
   name.str("");
}
//assuming we know whatever<3><65> was created...
cout << "Here is your variable whatever<3><65>: " << (variables["whatever<3><65>"]) << endl;