Thread: Compiles okay, but doesn't run.

  1. #16
    MFC killed my cat! manutd's Avatar
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    Think about it this way: argc is an int given to your program representing the number of command line arguments (including the program name). Thus for foo bar bas, argc = 3. argv, on the other hand, is a character array representing the arguments themselves. Thus, argv[0] is your program's name. For foo bar bas, argv[0] = "foo", argv[1] = "bar", and argv[2] = "bas". When VC++ compiles your program, it by default provides no arguments. Thus your program recognizes this and quits.
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  2. #17
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    karlawarla: are you studying at University of Westminster?;p

  3. #18
    c++ beginner so be nice! karlawarla's Avatar
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    Yup, are you??
    Microsoft: "You have questions, we having dancing paperclips"

  4. #19
    c++ beginner so be nice! karlawarla's Avatar
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    manutd, thank you for your post, i'll take note. :-)
    Microsoft: "You have questions, we having dancing paperclips"

  5. #20
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    karlawarla: ye, Internet Computing course;p

  6. #21
    c++ beginner so be nice! karlawarla's Avatar
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    kool, i'm doing the visualisation course, but taken programming methodology as my free choice, hence all the c++ questions lol
    Microsoft: "You have questions, we having dancing paperclips"

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