Hi everyone,
I am wondering how i would read in no input. what i mean by this is, a part of my program asks the user to "press enter to continue..". I basically want the program to halt and wait until the enter key is pressed and then the program should continue execution.
any ideas?
thank to everyone who read/replyied in advance.
dan.
>any ideas?
This is a common question that our FAQ answers.
My best code is written with the delete key.
thanks for the reply. So basically the answer to my query was the function 'getchar()'. I tried this function in program1 shown below and it worked fine, but when i used it in my real program below, it doesnt work at all. why is this?
program1
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Code:main() { printf("hit enter..."); getchar(); }
real program
----------------
Code:switch(choice) { case 1: { system("cls"); printf("\n"); printf("Conversion: Metres --> Kilometres\n"); printf("-----------------------------------\n"); printf("Please enter Metres: "); scanf("%d",&metres); while (metres < 0) { printf("\n"); printf("Invalid Length! Please re-enter Length:"); scanf("%d", &metres); } kilometres = (metres * METRE_TO_KILOM); printf("\n"); printf("%d metres = %d kilometres",metres, kilometres); printf("\nPress [Enter] to continue..."); getchar(); }; break;
>So basically the answer to my query was the function 'getchar()'.
That's only half of the answer. The other half covers the problem you're having now, which is extraneous characters in the stream being consumed by getchar. The FAQ page I linked to goes over all of this. You should read it more carefully.
My best code is written with the delete key.
Basically, scanf() ignores leading whitespace, but getchar() doesn't. In addition scanf() stops input into the variable when nonleading whitespace is encountered, but doesn't remove the nonleading whitespace from the input buffer. In your example,
scanf("%d", &metres);
leaves the newline char in the input buffer placed there at termination of input into metres when you pressed the enter key. The newline char is still waiting there when getchar() is called. Since there is something in the buffer when getchar() is called it takes the first remaining char out of the input buffer and allows the program to continue without pausing to wait for further input. To fix that you have to clear the input buffer before the call to getchar() in order to pause the program to wait for additional input. Unfortunately, using fflush() to clear the stdin stream buffer as shown in the FAQ isn't the way to clear the input buffer. In C++ the best way to clear the input buffer is something like this:
std::cin.ignore(std::numeric_limits<std::streamsiz e>::max());
but for most purposes just ignoring a sufficiently large number of char will work. In your case, you can probably get by by calling getchar() twice in succession since most likely you only have the one newline char remaining in the input buffer. That's not the most robust approach to the problem, but it probably is adequate for us duffers.
You're only born perfect.
Well, in C you would use
But in C++, as you were saying, you should useCode:int c; /* int for EOF */ while((c = getchar()) != '\n' && c != EOF); getchar();
since getchar() is a C function.Code:std::cin.ignore(std::numeric_limits<std::streamsize>::max()); std::cin.get();
dwk
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std::cin.ignore( std::numeric_limits<std::streamsize>::max());
should be
std::cin.ignore( std::numeric_limits<std::streamsize>::max(), '\n');
use this line :
system("Pause");
its exaculy wat u want.
Except for the fact that that's not portable and the solutions presented before are better...
Instead of scanf() which is dangerous and delicate, you should use fgets()...sscanf(). Which also happens to solve your extraneous characters in stream problem too.
Oh and this is the C++ forum.
Code:#include <stdio.h> void J(char*a){int f,i=0,c='1';for(;a[i]!='0';++i)if(i==81){ puts(a);return;}for(;c<='9';++c){for(f=0;f<9;++f)if(a[i-i%27+i%9 /3*3+f/3*9+f%3]==c||a[i%9+f*9]==c||a[i-i%9+f]==c)goto e;a[i]=c;J(a);a[i] ='0';e:;}}int main(int c,char**v){int t=0;if(c>1){for(;v[1][ t];++t);if(t==81){J(v[1]);return 0;}}puts("sudoku [0-9]{81}");return 1;}
