Problem with continue;

This is a discussion on Problem with continue; within the C++ Programming forums, part of the General Programming Boards category; Code: #include <iostream> using namespace std; int main() { for(double lusindex = 5; lusindex <= -4; lusindex--) { if(lusindex=0) continue; ...

  1. #1
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    Problem with continue;

    Code:
    #include <iostream>
    using namespace std;
    
    int main()
    {
        for(double lusindex = 5; lusindex <= -4; lusindex--)
        {
                   if(lusindex=0) continue;
                   cout<< "1/" <<lusindex<<" = "<<1/lusindex<<endl;
                   
                   
                   }
        cin.get();
    }
    no warnings.
    and it isn't couting something , it just shows blackscreen
    Last edited by hallo007; 10-29-2006 at 09:55 AM.

  2. #2
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    >> for(double lusindex = 5; lusindex <= 4; lusindex--)
    Your problem is in there.

    >> if(lusindex=0) continue;
    And this is wrong as well.

  3. #3
    Cat without Hat CornedBee's Avatar
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    The problem isn't with continue, it's that all your numbers and conditions make absolutely no sense. The loop never runs, and if it did, it would run forever. The equality operator is ==, not =.
    All the buzzt!
    CornedBee

    "There is not now, nor has there ever been, nor will there ever be, any programming language in which it is the least bit difficult to write bad code."
    - Flon's Law

  4. #4
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    so i got this now
    Code:
    #include <iostream>
    using namespace std;
    
    int main()
    {
        for(double lusindex = 5; lusindex <= -4; lusindex--)
        {
                   if(lusindex==0) continue;
                   cout<< "1/" <<lusindex<<" = "<<1/lusindex<<endl;
                   
                   
                   }
        cin.get();
    }
    how do i let the loop run?

  5. #5
    Its hard... But im here swgh's Avatar
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    What do you expect the output to be?
    Here is another example using continue that will skip the number 5

    Code:
    for ( int i = 0; i < 10; i++ )
    {
       if ( i == 5 )
          continue;
    }

  6. #6
    and the hat of wrongness Salem's Avatar
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    > double lusindex = 5; lusindex <= -4;
    This starts off by being false, so nothing happens.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  7. #7
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    how can you make it TRUE without chanching the numbers??

  8. #8
    Code Goddess Prelude's Avatar
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    >how can you make it TRUE without chanching the numbers??
    Define your own reality where the rules of mathematics no longer apply.
    My best code is written with the delete key.

  9. #9
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    lol , oke its not possible

  10. #10
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    i found it , it was very , very very stupid:s
    i writed lusindex <=-10 and it has to be >=
    lol

  11. #11
    and the hat of wrongness Salem's Avatar
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    > Define your own reality where the rules of mathematics no longer apply.
    Ah, you mean accountancy
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  12. #12
    Code Goddess Prelude's Avatar
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    >Ah, you mean accountancy
    I was thinking statistics, but same diff.
    My best code is written with the delete key.

  13. #13
    Reverse Engineer maxorator's Avatar
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    Code:
    #include <stdio.h>
     
    int main(void){
        int count, r_num[7], found, n;
        srand (time(0));
        for(count=0; count<7; count++){
            do{
                found=0;
                r_num[count] = rand()%45+1;
                for(n=0;n<count;n++){
                    if(r_num[n]==r_num[count]){
    	            found=1;
                        break;
        	        }
                }
            } while(found==1);
        }
        printf("%i %i %i %i %i %i %i",r_num[0],r_num[1],r_num[2],r_num[3],r_num[4],r_num[5],r_num[6]);
        fgetc(stdin);
        return 0;
    }
    Try lowering 45. The numbers will always be different, if you make 45 smaller than 7, the program never finishes the loop, because it hopes to find unused numbers in that range
    "The Internet treats censorship as damage and routes around it." - John Gilmore

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