strlen in expressions

This is a discussion on strlen in expressions within the C++ Programming forums, part of the General Programming Boards category; hi i am trying to make a program do this basically... int * strlen / strlen * strlen * strlen ...

  1. #1
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    strlen in expressions

    hi i am trying to make a program do this basically...

    int * strlen / strlen * strlen * strlen = an int

    i cannot figure out how to write that in code...

    i don't know if you cannot use strlen in a "formula" ? or what?

    thanks

    mathatmatically

    (5000 * 8) / (5 * 8 * 8)

    obviously using varibles in the program

    thanks again

  2. #2
    The superhaterodyne twomers's Avatar
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    Two methods:

    Code:
    int main( void )
    {
    	// USING *STRINGS
    
    	char *C_Str1;
    	char *C_Str2;
    	char *C_Str3;
    	char *C_Str4;
    	
    	// Intitalise the *strings
    
    	std::cout<< (5000*strlen(C_Str1))/(strlen(C_Str2)*strlen(C_Str3)*strlen(C_Str4));
    
    
    
    	// USING STD::STRING
    
    	std::string one;
    	std::string two;
    	std::string three;
    	std::string four;
    
    	// Initalise the std::strings
    	std::cout<< (5000 * one.size()) / (two.size() * three.size() * four.size());
    
    	return 0;
    }
    Or something to that effect.

  3. #3
    The larch
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    Try: x = (a*b)/(c*d*e);

    = is for assignment, you can't assign a value to a mathematical calculation, that's why x that gets the value is on the left.

    Also use brackets to make the statement non-ambigous.

  4. #4
    MFC killed my cat! manutd's Avatar
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    justforthis1, in the future could you make your titles a little more informative, for example "strlen in a formula" rather than "dumb newb question".
    Silence is better than unmeaning words.
    - Pythagoras
    My blog

  5. #5
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    ok thanks, that helps a lot, it works now anyways

    sorry about the title, i will do better next time

    thanks

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