function question

[unclebob]

hello, can someone please tell my why the following method of calling a function does not work??

#include <iostream>

int test1(int x){

return x* 12;

}

int test2(int x){

return x*12;

}

int main(){

int test1, test2; /* if i rename all occurences of these to something that is different that function names then it works*/

std::cin >> test1 >> test2;

std::cout << test1(test1) << std::endl << test2(test2) << std::endl;
}

i know what the problem is , in fact i have fixed it already but i cannot understand what is wrong.

if it illegal in c++ to use the name of a function as the parameter being passed to the said function?

please see my comment on where i fixed it to work

thank you

[Cat]

Well, it's very bad to have multiple things with the same name -- the compiler sees test1 and test2 as ints at that point in the code.

You could prefix the function calls with ::, but it would be far better to change the names.

[Desolation]

Yeah, it's just *way* better to give them a different name... And a meaningful name if possible.

[CornedBee]

Functions and variables share a namespace. By declaring two local variables called test1 and test2 in main(), you're hiding the functions of these names. The compiler can't find them.

[Salem]

Use the scope resolution operator

std::cout << ::test1(test1) << std::endl << ::test2(test2) << std::endl;

But it's far better to have different names for things.