Matching user info with data in file

I have a file with first and last names and phone numbers. Now, I need to writte a program that gets a name from a user, and if the name is in the file, display the corresponding number, but if the name is not in the file, the program writes a message saying that the name is not in the file. Also, the program needs to repeat the process until the user indicates that they would like to stop. Here is my code/psudocode...

Code:

#include <iostream>

using namespace std;

void GetFirstName and GetLastName( string)              // Function prototypes
void Printphonenumber (int )
void PrintQuestion (char)
int main()
{
    string FirstName;    // The outside temperature
    string LastName;
    int PhoneNumber
    char question;
    GetName(FirstName & LastName);                   // Function call
    PrintPhoneNumber(PhoneNumber;  
    PrintQuestion(Question);           // Function call
    
    
    
    // Declare and open input file
    ifstream inData;         // Input file of readings
    inData.open("phonedir.dat");
    if ( !inData )           // Did input file open correctly?
    {   // no
        cout << "Can't open input file." << endl;
        return 1;            // Terminate program
        
        
    }return 0;
}

//******************************************************************

void GetFirstName and GetLastName ( string FirstName and LastName )                   // Reference parameter

// This function prompts for a first name and last name to be entered

{
    cout << "Enter first name" << endl;
    cin >> FirstName;
    cout << "Enter Last name " << endl;
    cin >> LastName;
}

//******************************************************************

void Printphonenumber( string phonenumber )              // Value parameter

// This Function outputs the corresponding number or indicates that the name
// is not in the directory.  

If the first and last name are found in the file, then output corresponding number.
else
    cout << "The name could not be found in the directory

//*******************************************************************

void (PrintQuestion) (char)

//This function prints a question asking the user to find another number.  
//If no, terminate program.

cout << "Do you want to lookup another number? (Enter Y or N)" << 
cin >> char;
       If (char == 'Y')
       return();
       If (char == 'N')
       return 1;          //Terminate Program

Would this be valid?? if (FirstName && LastName=="phonedir.dat")
cout << phonenumber;
else
cout << "The name is not in the file";

You're missing a semicolon here:

Code:

int PhoneNumber;

Code:

If (char == 'Y')
       return();

C++ is case sensitive, so If isn't the same as if. char isn't a valid variable name.

Code:

return 1;          //Terminate Program

You can't return 1 from a void function. Nor will doing so terminate the program; only when you return from main() or call exit() will that happen.

Code:

void (PrintQuestion) (char)

That isn't a valid function definition; the ()s around the function name are extraneous (unnessesary), and you need to specify a variable name for the parameter (unlike in function prototypes).

GetName(FirstName & LastName); // Function call

I really think that that doesn't do what you want. To pass two parameters to a function, you need to declare the function as such.

You should read some of the tutorials, especially the function tutorial.

Code:

//******************************************************************
// Activity program
// This program outputs the phone number for a given name, 
//if the name is found in a file
//******************************************************************
#include <iostream>

using namespace std;

void GetFirstName and GetLastName( string, string)              // Function prototypes
void PrintPhoneNumber (int )
void PrintQuestion (char)
int main()
{
    string FirstName;    // The outside temperature
    string LastName;
    int PhoneNumber
    char question;

    GetFirstName and GetLastName(FirstName,LastName);                   // Function call
    PrintPhoneNumber(PhoneNumber);  
    PrintQuestion(question);           // Function call
    
    
    
    // Declare and open input file
    ifstream inData;         // Input file of readings
    inData.open("phonedir.dat");
    if ( !inData )           // Did input file open correctly?
    {   // no
        cout << "Can't open input file." << endl;
        return 1;            // Terminate program
    }
	return 0;
}

//******************************************************************

void GetFirstName and GetLastName ( string FirstName, string LastName )                   // Reference parameter

// This function prompts for a first name and last name to be entered

{
    cout << "Enter first name" << endl;
    cin >> FirstName;
    cout << "Enter Last name " << endl;
    cin >> LastName;
}

//******************************************************************

void Printphonenumber( string PhoneNumber )              // Value parameter

// This Function outputs the corresponding number or indicates that the name
// is not in the directory.  

if the first and last name are found in the file, then output corresponding number.
else
    cout << "The name could not be found in the directory

//*******************************************************************

void (PrintQuestion) (char)

//This function prints a question asking the user to find another number.  
//If no, terminate program.

cout << "Do you want to lookup another number? (Enter Y or N)" << 
cin >> question;
       if (question == 'Y')
       //repeat process
	   {
		   GetFirstName and GetLastName(FirstName,LastName);                   // Function call
	       PrintPhoneNumber(PhoneNumber); 
	   }
       if (question== 'N')
       return 1;          //Terminate Program