I need help with my program, it's a Julian Date conversion. The part that i'm having difficulty with is when you enter a julian date, there are 6 numbers after the decimal. How do i get the 6 numbers after the decimal so that i can calculate the hours, minutes and seconds?? here's my code:

my problem more specifically, is in the calculations portion where hours begins. to help understand what i mean:Code:#include <stdio.h> int main() { double jdn; long lc, nc, ic, jc; int day, month, year, hours, minutes, seconds, a, b, meridian ; /*print title*/ printf(" * * Julian Date Conversion * *\n") ; /*ask user for a Julian date */ printf ("Please enter a Julian Date:\n") ; scanf("%lf", &jdn) ; if (jdn <= 2299160) printf ("Error: You have entered an invalid number.") ; /* Perform calculations */ lc = jdn + 68569; nc = 4 * lc / 146097; lc = lc - (146097 * nc + 3) / 4; ic = 4000 * (lc + 1) / 1461001; lc = lc - 1461 * ic / 4 + 31; jc = 80 * lc / 2447; day = lc - 2447 * jc / 80; lc = jc / 11; month = jc + 2 - 12 * lc; year = 100 * (nc - 49) + ic + lc; hours= jdn % * 24 ; a= hours % 60 ; minutes= a * 60 ; b= minutes % 60 ; seconds= b * 60 ; if (meridian >= 12) printf ("p.m.") ; else printf ("a.m.") ; /* print date*/ printf("%d %d %d %d %d %d\n", month, day, year, hours, minutes, seconds, meridian); return 0; }

Calculation of time portion:

(0.1 days equals 0.1 * 24 hours = 2 hours (remainder 0.4 hours),

0.4 * 60 minutes = 24 minutes (remainder 0.0 seconds)

0.0 * 60 seconds = 0 seconds

I dont know how to get only the numbers after the decimal, or if there is another way i dont see it yet, so that i can calculate the hours, minutes, and seconds!! please help.