Passing arrays to functions?

This is a discussion on Passing arrays to functions? within the C++ Programming forums, part of the General Programming Boards category; I cant find out how it's the syntax. func(int [][] a) doesnt work... any hint? Thanks!...

  1. #1
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    Passing arrays to functions?

    I cant find out how it's the syntax.

    func(int [][] a) doesnt work... any hint?


  2. #2
    pwns nooblars
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    For multidimensional arrays I believe you have to specify the size in the function declaration and implementation (maybe not in the declaration?).

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    The Richness... Richie T's Avatar
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  4. #4
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    Thanks, checking now.

  5. #5
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    If you know the size at compile time, you specify the size (although the first dimension isn't necessary). If you don't know the size, or the array is dynamically allocated, you should use a vector instead. Otherwise you'll have to pass the size as an extra function parameter and pass the array by pointer.

  6. #6
    Frequently Quite Prolix dwks's Avatar
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    func(int [][] a)
    In C/C++, you have to put array indicies ([]) after the variable name, unlike in Java where you can put them before or after. And of course, as mentioned, all but the leftmost index must have sizes in them.

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  7. #7
    and the hat of int overfl Salem's Avatar
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    > func(int [][] a) doesnt work... any hint?
    Copy / paste works

    If your array is
    int arr[X][Y][Z];

    Then the function can(*) be written as
    void func ( int arr[X][Y][Z] );

    And you would call it with
    func( arr );

    (*) Some compilers will warn you about the redundant major dimension (the left-most one), so you can easily change it to
    void func ( int arr[ ][Y][Z] );

    If you want to spend extra effort, you can write it like this if you want
    void func ( int (*arr)[Y][Z] );

    All 3 forms are equivalent.
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