Thread: Remove elements from array

Of course you mean:

Code:

while(k != MAX)
{
      if(even[k] != 0)
      {       
            evenclean[i] = even[k] ;
            i++;
            
      }
      k++;
}

Yes, why not?

USE CODE TAGS

No, I'm writing it out every time...
Also, I have to edit it every time, because when you originally post, the upper-case words will be made lower-case with the first character upper-case and that's not done when editing the post.

Also, posting this thing is a good advertise to my cat (see my signature).

The site is loading too slowly.

It loads quite quickly for me. Maybe it's slow for foreign connections...

If you used a std::vector instead of an array, you could #include <algorithm> and write:

Code:

even.erase(
    std::remove_if(even.begin(), even.end(),
        std::bind2nd(std::equal_to<int>(), 0)),
    even.end());

At least assuming that you are dealing with ints. Of course, with an array you can still write:

Code:

// assuming even has not decayed into a pointer
int* even_end = even + sizeof(even) / sizeof(int);
even_end = std::remove_if(even, even_end, std::bind2nd(std::equal_to<int>(), 0));

Then you just use the range from even to even_end-1.