Can't figure out what's wrong with Function's Arguments

The first function I'm using is named Request

This function calls another function named PKADEN.

Request/

Code:

int PKADEN(char *, char *, char *, double &);

char s[100];
char ErrorMsg[150];
char PKADetail[500];
double FinalPKA;

PKADEN(s,ErrorMsg,PKADetail,&FinalPKA);

PKADEN/

Code:

int pkaden(char *s, char *ErrorMsg, char *PKADetail, double *FinalPKA)

Everything seems to be set up correctly, but when I try to compile it I get the following error:

Code:

Request - error C2664: 'pkaden' : cannot convert parameter 4 from 'double *__w64 ' to 'double &'

I'm using Visual Studio 2005 on Windows.

Thanks

Your prototype declares a reference, but your definition and invocation use a pointer.

Thanks for the info. I'm still pretty new to C++ and a little confused. Here's
what I came up with based on what you told me and it compiled:

request/

Code:

double FinalPKA; 
double *pFinalPKA = &FinalPKA;
char s[100];
char ErrorMsg[150];
char PKADetail[500];

int pkaden(char *,char *,char *,double *);

pkaden(s,ErrorMsg,PKADetail,pFinalPKA)

PKADEN/

Code:

int pkaden(char *s, char *ErrorMsg, char *PKADetail, double *pFinalPKA)

If you have a reference, you don't need to use the & operator when you call the function, it's all hidden from you

Code:

int PKADEN(char *, char *, char *, double &);
char s[100];
char ErrorMsg[150];
char PKADetail[500];
double FinalPKA;
PKADEN(s,ErrorMsg,PKADetail,FinalPKA);

But like a pointer, changes to the variable inside the function will appear in your variable.