Thread: Break in If statement

Good Morning:
I`ve read my books and several sites about "if" statements but I can`t get a feel for why "break" can`t be placed where I have placed it. DevC++ tells me it was expecting a primary expression before "break" but I`ve been trying different ways to give it what it wants and it stills pukes on me. Can you guys explain to me what I`m not doing correctly by looking at my example?

Code:

#include <iostream>
using namespace std;

int main() {
double c;
double f;
double t;

cout << "In order to convert celsius to farenheit \n";
cout << "or farenheit to celsius, enter either -c- or -f-";
 cin >> t;

 if (t != c || f)
 cout << "I`m outta here!";
 (break;)

 else if (t == f)
 {cout << "Enter celsius temperature to convert to farenheit: ";
 cin >> c;
 cout << "The temperature in farenheit is: " << (t * (1.8)) + 32;}

 else (t == c)
 {cout << "Enter farenheit temperature to convert to celsius: ";
 cin >> f;
 cout << "The temperature in celsius is: " << (t - 32) * .555;) }

system("PAUSE");
return 0;
}

??????????????????
Any advice is well appreciated...............

I wanted (t != f || c) to make sure the user would have to start over or get an error message if he did not enter "f" or "c". And thanks for the comment on indenting. I`m still fuzzy on this but will start doing it where I think it needs to be done.

Now....since break only works in loops can I put a return command at the if statement or demand that the user enter the proper letter?...........
Thanks to all for your replies.

Change (t != f || c) to ( (t!=f) || (t!=c) ). You may not necessarily need so many brackets. || and && etc operators don't work like you think they do.

Why do you want/need a break or a return?

Actually, now that you mention it, I should ask the user to correctly enter his request right? And not get out of the program. Thank You! And yes, I didn`t realize the switches had to be in their own parentheses. Thanks all!

>> ( t * 1.8 ) + 32
Don't you mean -> ( c * 1.8 ) + 32

>> (t - 32) * .555
and -> (f - 32) * .555


This would have been shown a lot sooner if you had formatted your code!! And for the above, they don't need ()'s, I think it's easier to see that way, but they need their own == or != -> ( t!=f || t!=c )

You need to put your if statement code in blocks, because after loops and condition statements, it will only execute at most one statement without braces, otherwise put your code in a block.

and do what twomers said.

Originally Posted by plain

Code:

double c;
double f;
double t;

cout << "In order to convert celsius to farenheit \n";
cout << "or farenheit to celsius, enter either -c- or -f-";
 cin >> t;

 if (t != c || f)

??????????????????
Any advice is well appreciated...............

You have asked the user to input the character 'c' or the character 'f'.

You are then storing their character in a double precision floating point number variable.

This is wrong.

You need a character variable in which to store their choice of fahrenheit or celsius. You must then compare this character variable first against one character constant and then against the other character constant.

Code:

double c;
double f;
char t;

cout << "In order to convert celsius to farenheit \n";
cout << "or farenheit to celsius, enter either -c- or -f-";
 cin >> t;

if (t != 'c' && t != 'f') {
  /* code for bad choice */
}

Next, you ask for an actual temperature and store it in the variable c

Code:

{cout << "Enter celsius temperature to convert to farenheit: ";
 cin >> c;
 cout << "The temperature in farenheit is: " << (t * (1.8)) + 32;}

but you use the variable t in your calculation where t is the character they input to choose either fahrenheit or celsius.

Hope this helps.

>> Now....since break only works in loops can I put a return command at the if statement or demand that the user enter the proper letter?
You should use a loop (e.g. while) which will loop until the user enters a valid character.

>> Change (t != f || c) to ( (t!=f) || (t!=c) ).
Already fixed in risby's code, but this is wrong. ( (t!=f) || (t!=c) ) will always be true, it should be &&.

Thanks everyone! LOL I can see I have more studying to do. You`ve all been great!