This program is suppoded to get an input of any number in any number system with a base from 2(binary) to 62, which includes all digits plus all capital and then all lower case letters.

It works sometimes, but if the output is more than 2 digits it will sometimes add 1 to the second digit, and it crashes if the output is more than 4 digits long.Code:#include <iostream> #include <string> using namespace std; string relet (int input) { string output; if (input == 0) output="0"; if (input == 1) output="1"; // ect, ect, ect. if (input == 61) output="z"; return output; } int unlet (string input) { int output; if (input == "0") output=0; if (input == "1") output=1; //ect, ect, ect. if (input == "z") output=61; return output; } int main () { string number; int base; int newbase; // (removed for space) This part gets user input for number, base, and newbase. const int length=number.length(); int input[length]; int * output; output[0]=0; // This loop puts the number into array "input", while reversing the numbers // and replaces letters with their decimal number equivilents int x=0; int y=length-1; string buffer; start1: buffer=number[y]; input[x]=unlet (buffer); x++; y--; if (x != length) goto start1; y=0; x=0; // -THE IMPORTANT PART- // subtracts 1 from the input substart: if (input[x] == 0) { input[x]=base-1; x++; if (x == length) // end if the input is 0 goto finish; goto substart; } input[x]--; x=0; // adds 1 to the output addstart: // this adds another digit to the output when nessecary if (x > y) { output = new int; output[x]=0; y++; } if (output[x] == newbase-1) { output[x]=0; x++; goto addstart; } output[x]++; x=0; goto substart; finish: //(removed) outputs the "output" array starting from the top down and uses the //"relet" function.

I have gone through the code countless times and cannot figure out what is making it not work. I can post the full code it anyone wants.