Thread: I am having a hard time understanding this...

So here's the code:

Code:

#include <iostream>
using namespace std;
int main() {
	int t,i, nums[3][4];
	for(t = 0; t < 3; ++t){
		for(i=0;i < 4; ++i) {
			nums[t][i] = (t*4)+i+1;
			cout << nums[t][i] << ' ';
		}
		cout  << "\n";
	}
	return 0;
}

And I just don't understand what this will do! My book says it will put the numbers 1 through eleven into each box, but I do not see how this is possible (I did compile this, I just don't understand how the answer was created).

So, when the first for loop runs, t = 0, so it increments once, then it runs the second for loop, and the I = 0, so it increments until it does not equal a number less than four (which will be four). Then the mathematical thing, that assigns the numbers to the arrays, puts the number nums[t][i], which would be: nums[1][4]. The number that is put there, is (4 * t) + i + 1. So the number put in nums[1][4] is 6. But when I run it I get this:

1 2 3 4
5 6 7 8
9 10 11 12


I know I am misunderstanding something. Which dimension comes first, when assigning things to an array? does: nums[1][4], the one refers to 1 down, or one across?

I refuse to label this thread as something as personally insulting as: "Noob question, please help".

>> when the first for loop runs, t = 0, so it increments once, then it runs the second for loop
This is where your understanding is wrong. The loops both start at 0. You run one iteration of the loop before you increment the variable, so the first time through, t is 0 and i is 0. That makes 4*0 + 0 + 1, which of course is 1.