why my termination routing is not called when program crashes

This is a discussion on why my termination routing is not called when program crashes within the C++ Programming forums, part of the General Programming Boards category; I recently upgraded my project from VC++ 6.0 to VC++ 2005. I am trying to define some error logging in ...

  1. #1
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    Mar 2006
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    why my termination routing is not called when program crashes

    I recently upgraded my project from VC++ 6.0 to VC++ 2005. I am trying to define some error logging in my custom termination routing. And here is what I did:

    1. define
    Code:
    void term_func()
    {
    // some custom processing
        exit(-1);
    }
    2. put
    set_terminate( term_func );
    somewhere in code that is definitely executed.

    3. I have no "try-catch" in the entire program.

    However when the program crashes --- due to a condition where fwrite to a null pointer --- term_func doesn't seem to be executed.

    Does anyone know why? Should I change some of the project/compile properties?

    Thanks in advance!

  2. #2
    carry on JaWiB's Avatar
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    Are you running it through the debugger? According to msdn, set_terminate only works outside the debugger.
    "Think not but that I know these things; or think
    I know them not: not therefore am I short
    Of knowing what I ought."
    -John Milton, Paradise Regained (1671)

    "Work hard and it might happen."
    -XSquared

  3. #3
    Registered User
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    Mar 2006
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    made sure it is outside the debugger, still no luck

    Well, here is what I did:

    1.
    Code:
    void term_func()
    {
    	cout << "term_func() was called by terminate().\n";
    
        exit(-1);
    }
    2. put
    set_terminate( term_func );
    somewhere in the program which executes early

    3. compile the code in "release" mode with /EHsc;

    4. open a console, type:
    test1.exe > a.out

    5. the program is a dialog window, when it crashes, nothing shows up in a.out

    Anyone knows why?

  4. #4
    Frequently Quite Prolix dwks's Avatar
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    Canada
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    Why not use the standard C function atexit()?

    Make the simplest program possible that demonstrates that. Does this do the same thing?
    Code:
    #include <stdio.h>
    
    int main(void) {
        puts("before");
        set_terminate(term_func);
        puts("after");
        return 0;
    }
    If that doesn't work, try atexit().
    dwk

    Seek and ye shall find. quaere et invenies.

    "Simplicity does not precede complexity, but follows it." -- Alan Perlis
    "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra
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  5. #5
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    I believe that since a segmentation fault occured, the OS closes your application without asking it to terminate because it is trying to access memory it does not have the permission to access.

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